如何更新特定Xelement?

XDocument doc;
...
XElement penItemValue = doc
     .Elements("MyStore")
     .Elements("Category")
     .Elements("itemName")
     .Single(itemName => itemName.Value == "Pen")
     .Parent
     .Element("itemValue");
penItemValue.Value = "123";

您可以找到它并使用linqtoxml更新它:

XElement root = XElement.Load("myXml.xml");

var penCategory = from category in root.Descendants("Category")
                  where category.Element("itemName") != null 
                     && category.Element("itemName").Value == "Pen"
                  select category;

penCategory.Element("itemName").Value = updatedValue;

我将使用xpath找到您要查找的元素,然后直接操作它。

对于xpath类似 //Category[itemName='Pen']/itemNumber 会找到元素 for more on Xpath see

以下(非常基本)片段对我来说是单声道的

using System.Xml;

namespace test
{

  class myclass
  {

  public static void Main(string[] argv)
  {
    XmlTextReader reader = new XmlTextReader(argv[0]);
    XmlDocument doc = new XmlDocument(); 
    doc.Load(reader);
    reader.Close();          
    XmlNode myNode;
    XmlElement root = doc.DocumentElement;
    myNode = root.SelectSingleNode("//Category[itemName='Pen']/itemNumber");

    myNode.InnerText = "18";

    doc.Save(argv[1]);
  }
}
}

使用xpath(大多数XML开发人员都熟悉这一点):

var xml = @"<?xml version=""1.0"" encoding=""utf-8""?>
  <MyStore>
    <Category>
      <itemName>Pen</itemName>
      <itemNumber>12</itemNumber>
    </Category>
    <Category>
      <itemName>Paper</itemName>
      <itemNumber>23</itemNumber>
    </Category>
  </MyStore>";

  var doc = new XmlDocument();
  doc.LoadXml(xml);
  var nav = doc.CreateNavigator();
  var iter = nav.Select("/MyStore/Category[itemName='Pen']/itemNumber");
  iter.MoveNext();
  iter.Current.SetValue("42");