如何在未知长度的计数器列表中使用并集和交集?[副本]

鉴于我知道有多少计数器,可以很容易地将 | 运算符获取计数器的联合,例如:

>>> from collections import Counter
>>> x = Counter([('a'), ('a', 'bc'), ('a', 'bc'), ('xyz', 'hooli')])
>>> y = Counter([('a'), ('a'), ('a'), ('asd', 'asd')])
>>> z = Counter([('a'), ('a'), ('a'), ('a'), ('a', 'bc')])
>>> x | y | z
Counter({'a': 4, ('a', 'bc'): 2, ('asd', 'asd'): 1, ('xyz', 'hooli'): 1})

但是,如果我有一个Counters列表作为函数的输入,我如何获得联合?

我必须循环每个计数器,然后执行并集吗?例如。

>>> xyz = [x,y,z]
>>> def counter_union(counters):
...     union = Counter()
...     for c in counters:
...             union = union | c
...     return union
... 
>>> counter_union(xyz)
Counter({'a': 4, ('a', 'bc'): 2, ('asd', 'asd'): 1, ('xyz', 'hooli'): 1})

还有别的办法吗?