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Order by不能与Union ALL my sql一起正常工作

union sql-order-by mysql

0

Ram Singh · 技术社区 · 9 年前

SELECT * from (SELECT eventid, eventdate,eventdates FROM events WHERE events.onlineclosingdate>curdate() order by onlineclosingdate asc) a
UNION  ALL
SELECT * from (SELECT eventid, eventdate,eventdates FROM events WHERE events.onlineclosingdate<=curdate() order by onlineclosingdate desc) as c

2 回复 | 直到 9 年前

1

2

P.Salmon 9 年前

例如,您可能需要识别2个日期周期块并使用条件顺序鉴于

drop table if exists t;
create table t (id int auto_increment primary key, dt date);

insert into t (dt) values
('2017-02-01'),('2017-10-01'),('2017-01-01'),
('2016-02-01'),('2016-10-01'),('2016-01-01');

select s.id,s.dt 
from
(
select 1 as srce,id,t.dt dt from t where dt > str_to_date('2016-12-31','%Y-%m-%d') 
union all
select 2,id,t.dt from t where dt <= str_to_date('2016-12-31','%Y-%m-%d') 
) s
order by srce asc,
            case when s.srce = 1 then s.dt end asc, 
            case when s.srce = 2 then s.dt end desc;

+----+------------+
| id | dt         |
+----+------------+
|  3 | 2017-01-01 |
|  1 | 2017-02-01 |
|  2 | 2017-10-01 |
|  5 | 2016-10-01 |
|  4 | 2016-02-01 |
|  6 | 2016-01-01 |
+----+------------+
6 rows in set (0.00 sec)

2

-1

Ramgy Borja 9 年前

联合两个查询并分组

SELECT * FROM (
SELECT a.eventid as `eventid`, a.eventdate as `eventdate`, a.eventdates as `eventdates`  FROM events a WHERE a.onlineclosingdate>curdate() order by a.onlineclosingdate asc)
UNION  ALL
SELECT c.eventid as `eventid`, c.eventdate as `eventdate`, c.eventdates as `eventdates` FROM events c WHERE c.onlineclosingdate<=curdate() order by c.onlineclosingdate desc)
) as `all`