Hibernate简单条件查询求解问题

我遇到了一个非常简单的条件查询问题:

sess    .createCriteria(user.class, "user")
        .user_c.add(Restrictions.eq("user.status", 1))
        .user_c.createAlias("user.userCategories","ucs")
        .add(Restrictions.eq("ucs.category_id",1));
        .add(Restrictions.eq("ucs.category_id",'yes'));
        .add(Restrictions.eq("ucs.category_id",2));
        .add(Restrictions.eq("ucs.category_id",'no')).list();

当然,这不会导致任何用户。

在SQL中,我也尝试过:

Select * FROM users user , ec_user_category uc where
    uc.user_login = user.login AND
    uc.status = 1 AND
    ((uc.category_id = 1 AND uc.value = 'yes') AND (uc.category_id = 2 AND uc.value = 'no'))

当然也没有用户

SQL中的两个解决方案,我认为不是很有效:

Select a.login from 
        (Select user.login , COUNT(*) as counter FROM users user , ec_user_category uc 
         where user.status = 1
         and uc.user_login = user.login 
         and 
            ((uc.category_id = 1 and uc.value = 'yes')

            OR (uc.category_id = 2 and uc.value = 'no'))

         GROUP BY user.login) a where a.counter = 2

其他:

Select * FROM users u 
    JOIN user_category uc on uc.user_login = u.login 
    JOIN user_category uc2 on uc2.user_login = u.login  
WHERE   (uc.category_id = 1 and uc.value = 'yes') 
        AND (uc2.category_id = 2 and uc2.value = 'no')

这些结果给了我很好的信息,但我认为这不是正确的方法。我将如何在Hibernate中用criteriaapi实现它。