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不返回筛选值的对象的筛选数组

reactjs javascript

morne · 技术社区 · 6 年前

(9) [{â¦}, {â¦}, {â¦}, {â¦}, {â¦}, {â¦}, {â¦}, {â¦}, {â¦}]
0: {tbi_tblid: 512100013, long_name: "", short_name: "", short_name2: "", trickysort: "", â¦}
1: {tbi_tblid: 512100013, long_name: "Diamorphine", short_name: "07", short_name2: "", trickysort: "Diamorphine", â¦}
2: {tbi_tblid: 512100013, long_name: "Fentanyl", short_name: "06", short_name2: "P", trickysort: "Fentanyl", â¦}
3: {tbi_tblid: 512100013, long_name: "Fentanyl  2 mcg/ml", short_name: "02", short_name2: "E", trickysort: "Fentanyl  2 mcg/ml", â¦}
4: {tbi_tblid: 512100013, long_name: "Fentanyl 4 mcg/ml", short_name: "03", short_name2: "E", trickysort: "Fentanyl 4 mcg/ml", â¦}
5: {tbi_tblid: 512100013, long_name: "Morphine", short_name: "04", short_name2: "P", trickysort: "Morphine", â¦}
6: {tbi_tblid: 512100013, long_name: "No Opioid", short_name: "01", short_name2: "", trickysort: "No Opioid", â¦}
7: {tbi_tblid: 512100013, long_name: "Other", short_name: "08", short_name2: "", trickysort: "Other", â¦}
8: {tbi_tblid: 512100013, long_name: "Oxycodone", short_name: "05", short_name2: "", trickysort: "Oxycodone", â¦}
length: 9
__proto__: Array(0)

我想过滤数组,使其只包含具有 short_name2 code

_correctOpioidOptions(type){
    if(type === 'epidural'){
        return {choiceOfOpioidsList_epi:this._filterList('e')}
    }else if(type === 'pca'){
        return {choiceOfOpioidsList_pca:this._filterList('p')}
    }
},
_filterList(code){
    let originalList = this.props.choiceOfOpioidsList;

    let newList = originalList.filter(function (item,code) {
        return item.short_name2.toLowerCase() === code;
    });

    console.log(newList);
},

但每次我都会得到一个空数组。我错过了什么?

我也试过以下方法。

_filterList(code){
    let originalList = this.props.choiceOfOpioidsList;

    let newList = originalList.filter(function (item,code) {
        if(return item.short_name2.toLowerCase() === code){
           return item;
        }
        return false;
    });

    console.log(newList);
},

3 回复 | 直到 6 年前

A l w a y s S u n n y 6 年前

你可以用这个试试 Array.prototype.filter() 只过滤掉 short_name2 code 例如 . 同时添加检查 短名称2 像这样变化无常 short_name2!="" 非空检查。

const arr_obj = [{"tbi_tblid":512100013,"long_name":"","short_name":"","short_name2":"","trickysort":""},{"tbi_tblid":512100013,"long_name":"Diamorphine","short_name":"07","short_name2":"","trickysort":"Diamorphine"},{"tbi_tblid":512100013,"long_name":"Fentanyl","short_name":"06","short_name2":"P","trickysort":"Fentanyl"},{"tbi_tblid":512100013,"long_name":"Fentanyl  2 mcg/ml","short_name":"02","short_name2":"E","trickysort":"Fentanyl  2 mcg/ml"},{"tbi_tblid":512100013,"long_name":"Fentanyl 4 mcg/ml","short_name":"03","short_name2":"E","trickysort":"Fentanyl 4 mcg/ml"},{"tbi_tblid":512100013,"long_name":"Morphine","short_name":"04","short_name2":"P","trickysort":"Morphine"},{"tbi_tblid":512100013,"long_name":"No Opioid","short_name":"01","short_name2":"","trickysort":"No Opioid"},{"tbi_tblid":512100013,"long_name":"Other","short_name":"08","short_name2":"","trickysort":"Other"},{"tbi_tblid":512100013,"long_name":"Oxycodone","short_name":"05","short_name2":"","trickysort":"Oxycodone"}]
let code = 'e';
result = arr_obj.filter((el,i)=>el.short_name2!="" && el.short_name2.toLowerCase()===code)
console.log(result);

bumbaneitr11 6 年前

如果是由于作用域的原因,它会将最近的作用域变量名带入游戏,将项与代码进行比较,代码是数组中项的索引。

James 6 年前

正如@yonexbat所提到的,您应该能够从.filter回调中删除错误的参数:

_filterList(code){
    let originalList = this.props.choiceOfOpioidsList;

    let newList = originalList.filter(function (item) {
        return item.short_name2.toLowerCase() === code;
    });

    console.log(newList);
}