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如何获取PHPDI容器?

php-di containers dependency-injection oop php

-1

Imnotapotato · 技术社区 · 5 年前

PHP DI ? 这是我迄今为止尝试过的变体之一。

Settings.php

<?php 
use MyApp\Core\Database;
use MyApp\Models\SystemUser;

return [
    'Database'      => new Database(), 
    'SystemUser'    => new SystemUser()
];

$containerBuilder   = new \DI\ContainerBuilder(); 
$containerBuilder->addDefinitions('Settings.php');
$container          = $containerBuilder->build();

SystemUserDetails.php

<?php 
namespace MyApp\Models\SystemUser;

use MyApp\Core\Database;
use MyApp\Core\Config;
use MyApp\Helpers\Session;


/**
 *
 *  System User Details Class
 *
 */
class SystemUserDetails 
{

/*=================================
=            Variables            =
=================================*/

    private $db;


/*===============================
=            Methods            =
================================*/

    /**
     *
     *  Construct
     *
     */
    public function __construct(Database $db)
    {
        # Get database instance
        // $this->db           = Database::getInstance();
        $this->db           = $db;
    }


    /**

函数MyApp\Models\SystemUser\SystemUserDetails的参数太少::u construct(),第54行的/www/MyApp/Models/SystemUser.php中传递了0,预期正好是1 文件:/www/myapp/models/SystemUser/SystemUserDetails.php

跟踪:

目前,我的主要 index.php 文件扩展名 init.php
然后我打电话给 App MyApp/Contollers/Login.php .
1. 这个 user_login

系统用户类:

namespace MyApp\Models;


class SystemUser
{

    public $id;

    # @obj SystemUser profile information (fullname, email, last_login, profile picture, etc')
    protected $systemUserDetatils;


    public function __construct($systemUserId = NULL)
    {
        # Create systemUserDedatils obj
        $this->systemUserDetatils   = new \MyApp\Models\SystemUser\SystemUserDetails();

        # If system_user passed
        if ( $systemUserId ) {

            # Set system user ID
            $this->id                   = $systemUserId;

            # Get SysUser data
            $this->systemUserDetatils->get($this);

        } else {

            # Check for sysUser id in the session:
            $systemUserId                   = $this->systemUserDetatils->getUserFromSession();

            # Get user data from session 
            if ( $systemUserId ) {

                # Set system user ID
                $this->id                   = $systemUserId;

                # Get SysUser data
                $this->systemUserDetatils->get($this);
            }
        }
    }
}

1 回复 | 直到 5 年前

yivi SilverLink 5 年前

在你的 SystemUser

$this->systemUserDetatils   = new \MyApp\Models\SystemUser\SystemUserDetails();

的构造函数 SystemUserDetails 需要一个 Database

打电话 new 直接地 您没有使用PHP-DI . 通过这样做,你就是躲藏依赖性,如果您想使用依赖性注入系统,这正是您想要避免的。

如果 系统用户 取决于 (“需要”) ,依赖项应该是显式的(例如,在其构造函数中声明)。

对于这样的系统。你在问题中显示的定义文件不符合要求 the best practices recommended by PHP-DI .

你的设计远非完美,我也不确定你的最终目标,但如果你做了这样的事情,它可能会起作用:

<?php
// src/Database.php

class Database {
    public function getDb() : string {
        return 'veryDb';
    }
}

<?php
// src/SystemUserDetails.php

class SystemUserDetails {

    protected $db;

    public function __construct(Database $db)
    {
        $this->db           = $db;
    }

    public function getDetails() {
       return "Got details using " . $this->db->getDb() . '.';
    }
}

<?php
// src/SystemUser.php
class SystemUser {

    protected $details;

    public function __construct(SystemUserDetails $details, $userId=null) {

        $this->details = $details;
    }

    public function getUser() {
       return "Found User. " .$this->details->getDetails();
    }
}

<?php
//init.php
require_once('vendor/autoload.php');

// build the container. notice I do not use a definition file.
$containerBuilder   = new \DI\ContainerBuilder();
$container          = $containerBuilder->build();

// get SystemUser instance from the container.
$userInstance = $container->get('SystemUser');

echo $userInstance->getUser(), "\n";

其结果是:

Found User. Got details using veryDb.