按类层次结构映射表中的鉴别器值分组

Is it possible to write a HQL query that groups results by the discriminator value of a table per class hierarchy mapping? 例如

"select discriminator d, count(*) c from Foo group by discriminator"

用一个像

<hibernate-mapping>
  <class abstract="true" name="Foo">
    <!-- SNIP -->
    <subclass name="Bar" discriminator-value="BAR">
      <!-- SNIP -->
    </subclass>
    <subclass name="Baz" discriminator-value="BAZ">
      <!-- SNIP -->
    </subclass>
  </class>
</hibernate-mapping>

可能的结果是

+-----+---+
| d   | c |
+-----+---+
| BAR | 3 |
| BAZ | 4 |
+-----+---|

所以我要找的是一个有效的替代品 discriminator 在我的HQL查询中。是否有这样的事情,或者我必须使用原始SQL?