在Python中,如何将epoch后的秒数转换为“datetime”对象?

datetime.datetime.fromtimestamp 如果你知道时区,你就可以产生和 time.gmtime

>>> datetime.datetime.fromtimestamp(1284286794)
datetime.datetime(2010, 9, 12, 11, 19, 54)

>>> datetime.datetime.utcfromtimestamp(1284286794)
datetime.datetime(2010, 9, 12, 10, 19, 54)

从epoch到 datetime strftime :

>>> ts_epoch = 1362301382
>>> ts = datetime.datetime.fromtimestamp(ts_epoch).strftime('%Y-%m-%d %H:%M:%S')
>>> ts
'2013-03-03 01:03:02'

从docs中,从epoch开始的秒数中获取时区感知的datetime对象的推荐方法是:

Python 3

from datetime import datetime, timezone
datetime.fromtimestamp(timestamp, timezone.utc)

Python 2 ,使用 pytz :

from datetime import datetime
import pytz
datetime.fromtimestamp(timestamp, pytz.utc)

fromtimestamp utcfromtimestamp

" This may raise ValueError, if the timestamp is out of the range of values supported by the platform C gmtime() function. It’s common for this to be restricted to years in 1970 through 2038

另请参见 Issue1646728

因为其他解决方案没有 T 分隔符或时间偏移(除 迈斯特罗 (回答):

from datetime import datetime, timezone
result = datetime.fromtimestamp(1463288494, timezone.utc).isoformat('T', 'microseconds')
print(result) # 2016-05-15T05:01:34.000000+00:00

fromtimestamp 因为如果我用 utcfromtimestamp .astimezone(...) 无论如何要得到补偿。

如果你不想一路 microseconds 您可以选择一个不同的单位与 isoformat() 方法。