SQL中如何根据条件加减前一行

我正试图根据 TranslationType

样本数据:

Id  TransactionType Value
-------------------------
1   Receipt          10
2   Issue             2
3   Receipt          10
4   Issue             5
5   Issue             3

我试过了,但我有一个问题,我得到的输出是错误的:

Id  TransactionType DiffValue
-----------------------------
1   Receipt          10
2   Issue             8
3   Receipt          22
4   Issue             5
5   Issue             2

差分值的期望输出:

Id  TransactionType  Value  DiffValue
---------------------------------------
1   Receipt           10        10
2   Issue              2         8  if issue then 10-2
3   Receipt           10        18  if receipt then 10+8 
4   Issue              5        13  if issue then 18-5
5   Issue              3        10  if issue then 13-3

SQL创建脚本:

DROP TABLE #Temp 

CREATE TABLE #Temp
(
    Id INT,
    TransactionType VARCHAR(50),
    value INT,
)

INSERT INTO #Temp (Id, TransactionType, value)
VALUES (1, 'Receipt', 10), (2, 'Issue', 2), (3, 'Receipt', 10),
       (4, 'Issue', 5), (5, 'Issue', 3)

SELECT * FROM #Temp

我的查询尝试:

SELECT
    Id,
    TransactionType,
    CASE 
       WHEN TransactionType = 'Receipt' 
          THEN SUM(value) OVER (ORDER BY Id ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW)  
       ELSE LAG(value) OVER (ORDER BY Id)  - value
    END AS DiffValue
FROM
    #Temp