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从列表中条件选择元组

tuples list python

RezAm · 技术社区 · 5 年前

我有一个元组列表,如下所示:

my_list = [(3, 3, 3, 3, 3), (1, 2, 3, 3, 3, 3), (2, 2, 2, 3, 3, 3), (1, 1, 1, 3, 3, 3, 3), (1, 1, 2, 2, 3, 3, 3), (1, 2, 2, 2, 2, 3, 3), (2, 2, 2, 2, 2, 2, 3), (1, 1, 1, 1, 2, 3, 3, 3), (1, 1, 1, 2, 2, 2, 3, 3), (1, 1, 2, 2, 2, 2, 2, 3), (1, 2, 2, 2, 2, 2, 2, 2), (1, 1, 1, 1, 1, 1, 3, 3, 3), (1, 1, 1, 1, 1, 2, 2, 3, 3), (1, 1, 1, 1, 2, 2, 2, 2, 3), (1, 1, 1, 2, 2, 2, 2, 2, 2), (1, 1, 1, 1, 1, 1, 1, 2, 3, 3), (1, 1, 1, 1, 1, 1, 2, 2, 2, 3), (1, 1, 1, 1, 1, 2, 2, 2, 2, 2), (1, 1, 1, 1, 1, 1, 1, 1, 1, 3, 3), (1, 1, 1, 1, 1, 1, 1, 1, 2, 2, 3), (1, 1, 1, 1, 1, 1, 1, 2, 2, 2, 2), (1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 3), (1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 2, 2), (1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 3), (1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 2), (1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 2), (1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1)]

我需要提取哪个数的元组 1 重复次数少于5次。我读过 here , here 以及其他一些帖子,基于这些,我写了如下:

results = []
for i in range(len(my_list)):           
    a = [elem for elem in my_list if my_list[i].count(1) < 5]
    results.append(a)

再给我一张单子就不行了。有人能告诉我我做错了什么吗?谢谢!

3 回复 | 直到 5 年前

Alain T. 5 年前

你很亲密。与Python一样,事情比我们想象的要简单:

 result = [t for t in my_list if t.count(1) < 5]

Ajax1234 5 年前

较短的解决方案可以利用列表理解 sum :

my_list = [(3, 3, 3, 3, 3), (1, 2, 3, 3, 3, 3), (2, 2, 2, 3, 3, 3), (1, 1, 1, 3, 3, 3, 3), (1, 1, 2, 2, 3, 3, 3), (1, 2, 2, 2, 2, 3, 3), (2, 2, 2, 2, 2, 2, 3), (1, 1, 1, 1, 2, 3, 3, 3), (1, 1, 1, 2, 2, 2, 3, 3), (1, 1, 2, 2, 2, 2, 2, 3), (1, 2, 2, 2, 2, 2, 2, 2), (1, 1, 1, 1, 1, 1, 3, 3, 3), (1, 1, 1, 1, 1, 2, 2, 3, 3), (1, 1, 1, 1, 2, 2, 2, 2, 3), (1, 1, 1, 2, 2, 2, 2, 2, 2), (1, 1, 1, 1, 1, 1, 1, 2, 3, 3), (1, 1, 1, 1, 1, 1, 2, 2, 2, 3), (1, 1, 1, 1, 1, 2, 2, 2, 2, 2), (1, 1, 1, 1, 1, 1, 1, 1, 1, 3, 3), (1, 1, 1, 1, 1, 1, 1, 1, 2, 2, 3), (1, 1, 1, 1, 1, 1, 1, 2, 2, 2, 2), (1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 3), (1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 2, 2), (1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 3), (1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 2), (1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 2), (1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1)]
result = [i for i in my_list if sum(c == 1 for c in i) < 5]

sahasrara62 5 年前

使用 filter 是个不错的选择。

my_list = [(3, 3, 3, 3, 3), (1, 2, 3, 3, 3, 3), (2, 2, 2, 3, 3, 3), (1, 1, 1, 3, 3, 3, 3), (1, 1, 2, 2, 3, 3, 3), (1, 2, 2, 2, 2, 3, 3), (2, 2, 2, 2, 2, 2, 3), (1, 1, 1, 1, 2, 3, 3, 3), (1, 1, 1, 2, 2, 2, 3, 3), (1, 1, 2, 2, 2, 2, 2, 3), (1, 2, 2, 2, 2, 2, 2, 2), (1, 1, 1, 1, 1, 1, 3, 3, 3), (1, 1, 1, 1, 1, 2, 2, 3, 3), (1, 1, 1, 1, 2, 2, 2, 2, 3), (1, 1, 1, 2, 2, 2, 2, 2, 2), (1, 1, 1, 1, 1, 1, 1, 2, 3, 3), (1, 1, 1, 1, 1, 1, 2, 2, 2, 3), (1, 1, 1, 1, 1, 2, 2, 2, 2, 2), (1, 1, 1, 1, 1, 1, 1, 1, 1, 3, 3), (1, 1, 1, 1, 1, 1, 1, 1, 2, 2, 3), (1, 1, 1, 1, 1, 1, 1, 2, 2, 2, 2), (1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 3), (1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 2, 2), (1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 3), (1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 2), (1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 2), (1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1)]


sol =list(filter (lambda x:x.count(1)<5, my_list))
print(sol)

输出

[(3, 3, 3, 3, 3),
 (1, 2, 3, 3, 3, 3),
 (2, 2, 2, 3, 3, 3),
 (1, 1, 1, 3, 3, 3, 3),
 (1, 1, 2, 2, 3, 3, 3),
 (1, 2, 2, 2, 2, 3, 3),
 (2, 2, 2, 2, 2, 2, 3),
 (1, 1, 1, 1, 2, 3, 3, 3),
 (1, 1, 1, 2, 2, 2, 3, 3),
 (1, 1, 2, 2, 2, 2, 2, 3),
 (1, 2, 2, 2, 2, 2, 2, 2),
 (1, 1, 1, 1, 2, 2, 2, 2, 3),
 (1, 1, 1, 2, 2, 2, 2, 2, 2)]