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有没有办法从asp.net webmethod中获取原始soap请求?

asmx soap web-services .net c#

Francisco Noriega · 技术社区 · 14 年前

例子:

public class Service1 : System.Web.Services.WebService
{
   [WebMethod]
   public int Add(int x, int y)
   {
       string request = getRawSOAPRequest();//How could you implement this part?
       //.. do something with complete soap request

       int sum = x + y;
       return sum;
   }
}

4 回复 | 直到 13 年前

nivlam 14 年前

soapextensions的另一种选择是实现ihttpmodule并在输入流传入时获取它。

public class LogModule : IHttpModule
{
    public void Init(HttpApplication context)
    {
        context.BeginRequest += this.OnBegin;
    }

    private void OnBegin(object sender, EventArgs e)
    {
        HttpApplication app = (HttpApplication)sender;
        HttpContext context = app.Context;

        byte[] buffer = new byte[context.Request.InputStream.Length];
        context.Request.InputStream.Read(buffer, 0, buffer.Length);
        context.Request.InputStream.Position = 0;

        string soapMessage = Encoding.ASCII.GetString(buffer);

        // Do something with soapMessage
    }

    public void Dispose()
    {
        throw new NotImplementedException();
    }
}

Eric Petroelje 14 年前

是的,您可以使用soapextensions来完成。这里有一个 nice article 贯穿整个过程。

Steven de Salas Alexander Bollaert 13 年前

你也可以阅读 contents of the Request.InputStream .

这样做更有用,例如在需要根据输入内容在webmethod中执行验证或其他操作的情况下。

using System;
using System.Collections.Generic;
using System.Web;
using System.Xml;
using System.IO;
using System.Text;
using System.Web.Services;
using System.Web.Services.Protocols;

namespace SoapRequestEcho
{
  [WebService(
  Namespace = "http://soap.request.echo.com/",
  Name = "SoapRequestEcho")]
  public class EchoWebService : WebService
  {

    [WebMethod(Description = "Echo Soap Request")]
    public XmlDocument EchoSoapRequest(int input)
    {
      // Initialize soap request XML
      XmlDocument xmlSoapRequest = new XmlDocument();

      // Get raw request body
      Stream receiveStream = HttpContext.Current.Request.InputStream

      // Move to begining of input stream and read
      receiveStream.Position = 0;
      using (StreamReader readStream = new StreamReader(receiveStream, Encoding.UTF8))
      {
        // Load into XML document
        xmlSoapRequest.Load(readStream);
      }

      // Return
      return xmlSoapRequest;
    }
  }
}

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