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如何根据数组元素的属性值将数组重新构造为对象?

helpers helper underscore.js arrays php

0

Monero Jeanniton · 技术社区 · 7 年前

我有一个数组(包含了“爱”的所有定义):

[
    {
        def: "a strong positive emotion of regard and affection",
        exemple: "hildren need a lot of love",
        class_: "noun"
    },
    {
        def: "any object of warm affection or devotion",
        exemple: "the theater was her first love",
        class_: "noun"
    },
    {
        def: "sexual activities (often including sexual intercourse) between two people",
        exemple: "he has a very complicated love life",
        class_: "noun"
    },


    {
        def: "have a great affection or liking for", 
        exemple: "She loves her boss and works hard for him",
        class_: "verb"
    },
    {
        def: "get pleasure from",
        exemple: "I love cooking",
        class_: "verb"
    },
]

是否可以使用 Underscore-PHP 或 PHP Array function

{
    noun: [
    {
        def: "a strong positive emotion of regard and affection",
        exemple: "hildren need a lot of love",
        class_: "noun"
    },
    {
        def: "any object of warm affection or devotion",
        exemple: "the theater was her first love",
        class_: "noun"
    },
    {
        def: "sexual activities (often including sexual intercourse) between two people",
        exemple: "he has a very complicated love life",
        class_: "noun"
    },
    ],


    verb: [
    {
        def: "have a great affection or liking for", 
        exemple: "She loves her boss and works hard for him",
        class_: "verb"
    },
    {
        def: "get pleasure from",
        exemple: "I love cooking",
        class_: "verb"
    },
    ]
}

1 回复 | 直到 7 年前

1

Rajdeep Paul 7 年前

将json字符串转换为分组一个是这样的:

json_decode() 函数获取多维数组。
循环遍历数组,根据需要对数组元素进行分组。
json_encode() 函数获取所需的json字符串。

(假设 $json 是原始json字符串)

// suppose $json is your original json string
$array = json_decode($json, true);

$resultArr = array();
foreach($array as $arr){
    $resultArr[$arr['class_']][] = $arr;
}

// display the resultant json string
echo json_encode($resultArr);