如何将多维数组转换为字典?

有时不使用linq更容易阅读,速度更快:

 var dict = new Dictionary<string, string[]>();
 for (int i = 0; i < arr.GetLength(0); i++)
      dict[arr[i, 0]] = new string[] { arr[i, 1], arr[i, 2] };

但当你觉得你真的需要使用linq时:

 Enumerable.Range(0, arr.GetLength(0))
     .ToDictionary(i => arr[i, 0], i => new string[] {arr[i, 1], arr[i, 2]});

多维数组是一个连续的内存块,因此您必须将它们视为单个数组。试试这个:

var dict = arr.Cast<string>() 
  .Select((s, i) => new { s, i })
  .GroupBy(s => s.i / arr.GetLength(1))
  .ToDictionary(
    g => g.First().s,
    g => g.Skip(1).Select(i => i.s).ToArray()
  );

解释如下:

// First, cast it to an IEnumerable<string>
var dict = arr.Cast<string>() 

  // Use the Select overload that lets us get the index of the element,
  // And we capture the element's index (i), along with the element itself (s)
  // and put them together into an anonymous type [1]
  .Select((s, i) => new { s, i })

  // .GetLength(dimension) is a method on multidimensional arrays to 
  // get the length of a given dimension (pretty self-explanatory)
  // In this case, we want the second dimension, or how wide each 
  // row is: [x,y] <- we want y
  // Divide the element index (s.i) by that length to get the row index 
  // for that element
  .GroupBy(s => s.i / arr.GetLength(1))

  // Now we have an Grouping<int, IEnumerable<anonymous{string,int}>>
  .ToDictionary(

    // We don't care about the key, since it's the row index, what we want
    // is the string value (the `s` property) from first element in the row
    g => g.First().s,

    // For the value, we want to skip the first element, and extract
    // the string values (the `s` property), and then convert to an array
    g => g.Skip(1).Select(i => i.s).ToArray()
  );

[1]:见 here 有关匿名类型的文档。

这是我能想到的最简单的方法:

var arr = new int[4, 3]
{
    { 1, 2, 3 },
    { 3, 5, 7 },
    { 5, 8, 11 },
    { 7, 11, 15 },
};

var dict = arr.Cast<int>().Buffer(3).ToDictionary(x => x[0], x => x.Skip(1).ToArray());

这给了我:

你只需要使用“system.interactive”来获取 Buffer 接线员。

或者使用此实现:

public static IEnumerable<T[]> Buffer<T>(this IEnumerable<T> source, int count)
    =>
        source
            .Select((t, i) => new { t, i })
            .GroupBy(x => x.i / count)
            .Select(x => x.Select(y => y.t).ToArray());

我想你的方法是对的,我唯一怀疑的是你的数组是否是静态的?

arr.Select((value, index) => new { value, index }) .ToDictionary(x => x.index, x => new string[2]{x.value[x.index][1],x.value[x.index][2]}));

注意:我无法执行和检查代码!对不起的。

我已经用过整数了。请根据您的要求更改。

public static void Main()
{ 
    int row=0 , col=0;
    int[,] array = new int[,]
    {
     { 1, 2, 3 },
     { 4, 5, 6 }, 
     { 7, 8, 9 },
     { 10, 11, 12 } 
    };

    int flag=0;

    for (int i = 0; i < array.Rank; i++)
    {
                if(flag==0)
                {
        row= array.GetLength(i);
                    flag=1;
                }
                else
                {

         col= array.GetLength(i);       
                }

        }

    Dictionary<int,int[,]> dictionary = new Dictionary<int, int[,]>();

    for(int i=0;i<row;i++)
    {

        dictionary.Add(array[i,0],new int[, ]{{array[i,1]},{array[i,2]}});

    }

    Console.WriteLine(dictionary[4].GetValue(0,0));

}