如何在Django CRUD中自定义auth.User管理页?

我终于在admin.py文件中这样做了:

from django.contrib.auth.admin import UserAdmin
from django.contrib.auth.models import User

UserAdmin.list_display = ('email', 'first_name', 'last_name', 'is_active', 'date_joined', 'is_staff')

admin.site.unregister(User)
admin.site.register(User, UserAdmin)

另一种方法是扩展UserAdmin类。

from django.contrib.auth.admin import UserAdmin
from django.contrib.auth.models import User

class CustomUserAdmin(UserAdmin):
    def __init__(self, *args, **kwargs):
        super(UserAdmin,self).__init__(*args, **kwargs)
        UserAdmin.list_display = list(UserAdmin.list_display) + ['date_joined', 'some_function']

    # Function to count objects of each user from another Model (where user is FK)
    def some_function(self, obj):
        return obj.another_model_set.count()


admin.site.unregister(User)
admin.site.register(User, CustomUserAdmin)

在admin.py中

导入UserAdmin

from django.contrib.auth.admin import UserAdmin

输入需要的字段:

UserAdmin.list_display = ('email','is_active')  # Put what you need

就这些!它适用于Django3

User 您的订阅日期字段是 subscription_date admin.py

class UserAdmin(admin.ModelAdmin):
    list_display = ('subscription_date',)

admin.site.register(User, UserAdmin)