Python:如何确定列表中特定数量的项目是否相同?

假设你的 数字 变量是由5个元素(5张卡)组成的列表,您可以尝试以下操作:

from collections import Counter
numbers = [1,4,5,5,6]
c = Counter(numbers)

这利用了 awesome Counter class . :)

拥有计数器后,您可以通过执行以下操作来检查最常见的发生次数:

# 0 is to get the most common, 1 is to get the number
max_occurrencies = c.most_common()[0][1]   
# this will result in max_occurrencies=2 (two fives)

如果您还想知道哪张卡如此频繁,可以使用元组解包一次性获得这两个信息:

card, max_occurrencies = c.most_common()[0]
# this will result in card=5, max_occurrencies=2 (two fives)

您还可以将这些计数存储在 collections.defaultdict ,并检查最大出现次数是否等于您的特定项目数:

from collections import defaultdict

def check_cards(hand, count):
    d = defaultdict(int)

    for card in hand:
        rank = card[0]
        d[rank] += 1

    return max(d.values()) == count:

其工作原理如下:

>>> check_cards(['AS', 'AC', 'AD', 'AH', 'QS'], 4) # 4 Aces
True
>>> check_cards(['AS', 'AC', 'AD', '2H', 'QS'], 4) # Only 3 Aces
False

更好的是 collections.Counter() ,如所示 @Gabe's 答复:

from collections import Counter
from operator import itemgetter

def check_cards(hand, count):
    return max(Counter(map(itemgetter(0), hand)).values()) == count