Swift如何打开显示电话号码的拨号程序?

使用这个:

let phoneNumber = "+123123123"
let numberUrl = URL(string: "tel://\(phoneNumber)")!
if UIApplication.shared.canOpenURL(numberUrl) {
    UIApplication.shared.open(numberUrl)
}

相关链接:

1. https://developer.apple.com/library/archive/releasenotes/General/RN-iOSSDK-10.3/
2. https://developer.apple.com/documentation/uikit/uiapplication/1648685-open

您无法在iOS的手机应用程序中打开拨号器/键盘。或者,您可以在视图控制器中设计自己的键盘,为按键添加音调并收集数字。一旦你有了号码,使用以下方式拨打电话:

func call() {

    let app = UIApplication.shared

    guard let number = URL(string: "tel://" + "1234567890"), app.canOpenURL(number) else {
        return
    }
    app.openURL(number)
}