rowspan
向下突出到所选行-因为这会导致单元格索引与“表观”索引不同。即,表格第二列中的每个单元格不一定具有
cellIndex==1
.
function OffsetCells($tbody) {
// if already indexed, we don't need to re-do it
if (!$tbody.data('isOffset').value) {
// set offset for all cells to zero
$tbody.find('td').data('offset', { value: 0 });
// it's not already indexed, so get the cells that span multiple rows
// capitalization of 'rowSpan' is important for IE
var $rowSpanners = $tbody.find('td[rowSpan!=1]');
$rowSpanners.each(function() {
var $rowSpanningCell = $(this);
// we need to select all the cells to the 'apparent' right of this cell,
// so we need this cell's apparent position
// multiplying by one is easier than parseInt() to ensure conversion
$rowSpanningCell.data('apparentIndex', { value: this.cellIndex * 1 + $rowSpanningCell.data('offset').value });
// we also need to know what row this cell is in
/*???*/ $rowSpanningCell.data('rowIndex', { value: $rowSpanningCell.parent('tr').get(0).rowIndex });
// down to business:
$tbody.parent('table') // get the whole table
.find('tr') // get all the rows in the table
.slice($rowSpanningCell.data('rowIndex').value + 1, $rowSpanningCell.data('rowIndex').value + this.rowSpan) // narrow selection to the applicable rows
.find('td') // get the cells in the chosen rows
.filter(function(index) { // get the cells to the apparent right of this one.
return index + $(this).data('offset').value >= $rowSpanningCell.data('apparentIndex').value;
}).each(function() {
$(this).data('offset', { value: $(this).data('offset').value + 1 });
});
});
$tbody.data('isOffset', { value: true });
}
}
此代码在IE中运行良好,但在
/*???*/
线我已经把范围缩小到
$rowSpanningCell.parent('tr').get(0).rowIndex
部分我已经尝试了我所能想到的一切,但仍然无法让它返回
rowIndex
alert($rowSpanningCell.parent('tr').get(0).nodeName)
我得到了预期的结果
<TR>
,所以我知道我的选择是正确的。该行的每个其他属性的每个其他值似乎都返回罚款-但是
行索引