这就是我思考的方向
我给了你9个级别,但模式很容易看到和扩展
如果没有正确的序列,我默认按节点的字母顺序排列。
它还支持多个根节点
实例
Select A.*
,Nodes = concat('/',dense_rank() over (Order By N1),'/'
,left(nullif(dense_rank() over (Partition By N1 Order By N2)-1,0),5)+'/'
,left(nullif(dense_rank() over (Partition By N1,N2 Order By N3)-1,0),5)+'/'
,left(nullif(dense_rank() over (Partition By N1,N2,N3 Order By N4)-1,0),5)+'/'
,left(nullif(dense_rank() over (Partition By N1,N2,N3,N4 Order By N5)-1,0),5)+'/'
,left(nullif(dense_rank() over (Partition By N1,N2,N3,N4,N5 Order By N6)-1,0),5)+'/'
,left(nullif(dense_rank() over (Partition By N1,N2,N3,N4,N5,N6 Order By N7)-1,0),5)+'/'
,left(nullif(dense_rank() over (Partition By N1,N2,N3,N4,N5,N6,N7 Order By N8)-1,0),5)+'/'
,left(nullif(dense_rank() over (Partition By N1,N2,N3,N4,N5,N6,N7,N8 Order By N9)-1,0),5)+'/'
)
From YourTable A
Cross Apply (
Select N1 = ltrim(rtrim(xDim.value('/x[1]','varchar(max)')))
,N2 = ltrim(rtrim(xDim.value('/x[2]','varchar(max)')))
,N3 = ltrim(rtrim(xDim.value('/x[3]','varchar(max)')))
,N4 = ltrim(rtrim(xDim.value('/x[4]','varchar(max)')))
,N5 = ltrim(rtrim(xDim.value('/x[5]','varchar(max)')))
,N6 = ltrim(rtrim(xDim.value('/x[6]','varchar(max)')))
,N7 = ltrim(rtrim(xDim.value('/x[7]','varchar(max)')))
,N8 = ltrim(rtrim(xDim.value('/x[8]','varchar(max)')))
,N9 = ltrim(rtrim(xDim.value('/x[9]','varchar(max)')))
From (Select Cast('<x>' + replace((Select replace(stuff([canonicalName],1,1,''),'\','§§Split§§') as [*] For XML Path('')),'§§Split§§','</x><x>')+'</x>' as xml) as xDim) as A
) B
Order By 1
退换商品
canonicalName Nodes
\domain.com\ /1/
\domain.com\Corporate /1/1/
\domain.com\Corporate\Accounting /1/1/1/
\domain.com\Corporate\Hr /1/1/2/
\domain.com\Security\ /1/2/
\domain.com\Security\Administrative /1/2/1/
\domain.com\Security\Executive /1/2/2/
\domain.com\Security\Servers /1/2/3/
\domain.com\Users\ /1/3/
\domain.com\Users\Sales /1/3/1/
\domain.com\Users\Whatever /1/3/2/