如何在python中获取具有特定文件夹同级的特定文件夹

基本上,您似乎想找到一组特定的子文件夹 sets 这是很自然的,这使得这是一件相当容易的事情。在检查相等性时,它们的使用也消除了顺序依赖性。

import os

start_path = '/'
target = 'zeFolder'
siblings = ['brotherOne', 'brotherTwo']
sought = set([target] + siblings)

for root, dirs, files in os.walk(start_path):
    if sought == set(dirs):
        print('found')

如何使用列表

import os

folder = 'zeFolder'
brothers = ['brotherOne', 'brotherTwo']

for dirpath, dirnames, filenames in os.walk('/'):
    if folder in dirnames and all(brother in dirnames for brother in brothers):
        print 'matches on %s' % os.path.join(dirpath, 'zeFolder') 

或套

import os

folder = 'zeFolder'
brothers = set(['brotherOne', 'brotherTwo', folder])

for dirpath, dirnames, filenames in os.walk('/'):
    if set(dirnames).issuperset(brothers) :
        print 'matches on %s' % os.path.join(dirpath, 'zeFolder') 

对我来说,两个人的速度都一样。

import os
import glob

filelist = glob.glob(r"dad1/*brotherOne")
for f in filelist:
    print(f)

filelist = glob.glob(r"dad1/*brotherTwo")
for f in filelist:
    print(f)

你也可以试试地球仪技术。在for循环中执行任何您想执行的操作。