如何防止currentCellChanged信号在qt或跳过“处理”?

我有一个菜单项和一个带有插槽的qtablewidget:

connect(ui->actionOpen, &QAction::triggered, this, &MainWindow::open);
connect(ui->fooTableWidget, SIGNAL(currentCellChanged(int, int, int, int)), 
    this, SLOT(checkFooChanged(int, int, int, int)));

打开文件时,我试图通过使用标志变量来防止在插槽中执行任何操作:

void MainWindow::open()
{
    flag = false;
    ui->fooTableWidget->insertRow(0);
    ui->fooTableWidget->insertRow(1);
    flag = true;
}

void MainWindow::checkFooChanged(int row, int, int previousRow, int)
{
    if (flag && row != previousRow)
    {
        qDebug() << "processing";
        // do something here 
    }
}

但是,当我单击“打开”时,“处理”部分仍然会在“打开”完成后运行。是否有更可靠的方法暂时禁用checkfoochanged“处理”,直到完全打开为止?注意:当控件返回给用户时,需要将flag设置回true,以便在用户更改footablewidget上的行时调用“处理”。

更新

以下是一个最小的例子以及Eyllanesc的建议:

#include <QDebug>
#include <QTableWidget>
#include <QFileDialog>
#include "mainwindow.h"
#include "ui_mainwindow.h"

MainWindow::MainWindow(QWidget *parent) :
    QMainWindow(parent),
    ui(new Ui::MainWindow)
{
    ui->setupUi(this);
    ui->fooTableWidget->setColumnCount(1);
    connect(ui->actionOpen, &QAction::triggered, this, &MainWindow::open);
    connect(ui->fooTableWidget, SIGNAL(currentCellChanged(int, int, int, int)),
        this, SLOT(checkFooChanged(int, int, int, int)));
}

MainWindow::~MainWindow()
{
    delete ui;
}

void MainWindow::checkFooChanged(int row, int, int previousRow, int)
{
    qDebug() << "processing: " << row << ' ' << previousRow;
}

void MainWindow::open()
{
    QString fileName;
    fileName = QFileDialog::getOpenFileName(this, tr("Open"), "", "(*.emx)");
    if (fileName.isEmpty())
        return;
    qDebug() << "file " << fileName;
    ui->fooTableWidget->blockSignals(true);
    ui->fooTableWidget->setRowCount(0);
    ui->fooTableWidget->insertRow(0);
    QTableWidgetItem *item;
    item = new QTableWidgetItem();
    ui->fooTableWidget->setItem(0, 0, item);
    item->setText("Oh hi there!");
    ui->fooTableWidget->blockSignals(false);
}

所以这个问题似乎是由主窗口重新聚焦引起的。