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将元组列表转换为以整个元组为键的dict列表

tuples dictionary list python-3.x

Ammar Sabir Cheema · 技术社区 · 2 年前

我有一个嵌套的元组列表,如下所示,

>>> my_nested_list_of_tuples
  [[('AU041133(+)', 'Qtrt1'), ('Ahr(+)', 'Mex3c'), ('Arid3a(+)', 'Hmgb1')],     
  [('AU041133(+)', 'Topors'), ('Ahr(+)', 'Mex3c'), ('Arid3a(+)', 'Hmgb1')],   
  [('AU041133(+)', 'Tm9sf3'), ('Ahr(+)', 'Mex3c'), ('Arid3a(+)', 'Hmgb1')], 
  [('AU041133(+)', 'Gsn'), ('Ahr(+)', 'Ireb2'), ('Arid3a(+)', 'Hmgb1')],
  [('AU041133(+)', 'Tm9sf3'), ('Ahr(+)', 'Ilf3'), ('Arid3a(+)', 'Arid3a')]]

我想将上面嵌套的元组列表转换为字典列表,整个元组作为键,0作为值,如下所示

 [{('AU041133(+)', 'Qtrt1'): 0, ('Ahr(+)', 'Mex3c'): 0, ('Arid3a(+)', 'Hmgb1'): 0},
 {('AU041133(+)', 'Topors'): 0, ('Ahr(+)', 'Mex3c'): 0, ('Arid3a(+)', 'Hmgb1'): 0},  
 {('AU041133(+)', 'Tm9sf3'): 0, ('Ahr(+)', 'Mex3c'): 0, ('Arid3a(+)', 'Hmgb1'): 0}, 
 {('AU041133(+)', 'Gsn'): 0, ('Ahr(+)', 'Ireb2'): 0, ('Arid3a(+)', 'Hmgb1'): 0}, 
 {('AU041133(+)', 'Tm9sf3'): 0, ('Ahr(+)', 'Ilf3'): 0, ('Arid3a(+)', 'Arid3a'): 0}]

我尝试了各种方法来实现这一点,但我没有成功,下面给出了我尝试的一种方法,

>>> d = defaultdict(list)
>>> dk=[] # for populating with list of dicts
>>> for k in my_tops: 
...     for i,v in k:
...          d[(i,v)].append(0)
...     dk.append(d)
... 

>>> dk
[defaultdict(<class 'list'>, {('AU041133(+)', 'Qtrt1'): [0], ('Ahr(+)', 'Mex3c'):  [0, 0, 0], 
('Arid3a(+)', 'Hmgb1'): [0, 0, 0, 0], ('AU041133(+)', 'Topors'): [0], ('AU041133(+)', 'Tm9sf3'): [0, 0], 
('AU041133(+)', 'Gsn'): [0], ('Ahr(+)', 'Ireb2'): [0], ('Ahr(+)', 'Ilf3'): [0], ('Arid3a(+)', 'Arid3a'): [0]}), 
defaultdict(<class 'list'>, {('AU041133(+)', 'Qtrt1'): [0], ('Ahr(+)', 'Mex3c'): [0, 0, 0], 
('Arid3a(+)', 'Hmgb1'): [0, 0, 0, 0], ('AU041133(+)', 'Topors'): [0],  ('AU041133(+)', 'Tm9sf3'): [0, 0], 
('AU041133(+)', 'Gsn'): [0], ('Ahr(+)', 'Ireb2'): [0], ('Ahr(+)', 'Ilf3'): [0],  ('Arid3a(+)', 'Arid3a'): [0]}), 
defaultdict(<class 'list'>, {('AU041133(+)', 'Qtrt1'): [0], ('Ahr(+)', 'Mex3c'): [0, 0, 0], 
('Arid3a(+)', 'Hmgb1'): [0, 0, 0, 0], ('AU041133(+)', 'Topors'): [0], ('AU041133(+)', 'Tm9sf3'): [0, 0], 
('AU041133(+)', 'Gsn'): [0], ('Ahr(+)', 'Ireb2'): [0], ('Ahr(+)', 'Ilf3'): [0], ('Arid3a(+)', 'Arid3a'): [0]}), 
defaultdict(<class 'list'>, {('AU041133(+)', 'Qtrt1'): [0], ('Ahr(+)', 'Mex3c'): [0, 0, 0], 
 ('Arid3a(+)', 'Hmgb1'): [0, 0, 0, 0], ('AU041133(+)', 'Topors'): [0], ('AU041133(+)', 'Tm9sf3'): [0, 0], 
('AU041133(+)', 'Gsn'): [0], ('Ahr(+)', 'Ireb2'): [0], ('Ahr(+)', 'Ilf3'): [0], ('Arid3a(+)', 'Arid3a'): [0]}), 
defaultdict(<class 'list'>, {('AU041133(+)', 'Qtrt1'): [0], ('Ahr(+)', 'Mex3c'): [0, 0, 0], ('Arid3a(+)', 'Hmgb1'): [0, 0, 0, 0], 
('AU041133(+)', 'Topors'): [0], ('AU041133(+)', 'Tm9sf3'): [0, 0], 
('AU041133(+)', 'Gsn'): [0], ('Ahr(+)', 'Ireb2'): [0], ('Ahr(+)', 'Ilf3'): [0],  ('Arid3a(+)', 'Arid3a'): [0]})]

1 回复 | 直到 2 年前

Sala 2 年前

dict_list=[]
>>> for row in my_nested_list_of_tuples:
...     dict_list.append({key:0 for key in row})

[{('AU041133(+)', 'Qtrt1'): 0, ('Ahr(+)', 'Mex3c'): 0, ('Arid3a(+)', 'Hmgb1'): 0},
 {('AU041133(+)', 'Topors'): 0, ('Ahr(+)', 'Mex3c'): 0, ('Arid3a(+)', 'Hmgb1'): 0},
 {('AU041133(+)', 'Tm9sf3'): 0, ('Ahr(+)', 'Mex3c'): 0, ('Arid3a(+)', 'Hmgb1'): 0},
 {('AU041133(+)', 'Gsn'): 0, ('Ahr(+)', 'Ireb2'): 0, ('Arid3a(+)', 'Hmgb1'): 0},
 {('AU041133(+)', 'Tm9sf3'): 0, ('Ahr(+)', 'Ilf3'): 0, ('Arid3a(+)', 'Arid3a'): 0}]