将字符串与公共中间部分合并

从盒子里我什么都不知道。 但这应该做到:

function merge_overlap($left, $right) {
  // continue checking larger portions of $right
  for($l = 1; $l < strlen($right); $l++) {
    // if we no longer have a matching subsection return what's left appended
    if(strpos($left, substr($right, 0, $l)) === false) {
      return $left . substr($right, $l - 1);
    }
  }

  // no overlap, return all
  return $left . $right;
}

编辑:有一个海外建筑运营管理局,更新。

更新:这不是解决方案,strpos()在左路径的任何位置匹配文本的部分,应该与tail进行比较。

以下是我的方法的正确实现:

function merge_overlap($left, $right) {
  $l = strlen($right);
  // keep checking smaller portions of right
  while($l > 0 && substr($left, $l * -1) != substr($right, 0, $l))
    $l--;

  return $left . substr($right, $l);
}

它有点难看,并且假设您的字符串总是以“/”开头。但是:

$a = '/srv/http/projects/name';
$b = '/projects/name/some/dir';

$merged = array_merge(explode('/', $a), explode('/', $b) );
$unique = array_unique($merged);

$c = implode('/', $unique);

print $c; // prints "/srv/http/projects/name/some/dir"

function f($a, $b)
{
  for($i=0; count($a) > $i ; $i++)
  {
    if(strpos($b, substr($a, $i)) !== FALSE)
      return substr($a, 0, $i-1).$b;
  } 
  return $a.$b;
}

试试这个:

function merge($a, $b) {
    // divide into path parts to compare the parts
    $start = preg_split('%/%', $a, -1, PREG_SPLIT_NO_EMPTY);
    $end = preg_split('%/%', $b, -1, PREG_SPLIT_NO_EMPTY);

    // if the first part of the first path is in the second path than switch
    if(in_array($start[0], $end)) {
       $temp = $start;
       $start = $end;
       $end = $temp;
    }
    $parts = array();
    // get the index of the last part of the first path in the second path
    $index = array_search($start[count($start)-1], $end);

    // if the part exists, remove the first parts of the second path
    if($index !== false) {
        $parts = array_merge($start, array_slice($end, $index+1));
    }
    return '/' . join('/', $parts);
}


$a = '/srv/http/projects/name';
$b = '/projects/name/some/dir';

print merge($a, $b);

这给了我:

/srv/http/projects/name/some/dir

如果路径没有公共部分,则可能必须提供默认值或其他值。

我认为没有一种“聪明”的方法可以做到这一点。只是重复一遍 $a 直到所有最右边的令牌在 $b .

这里我 explode() 两个字符串,以便我可以通过 array_slice() .

$a = '/srv/http/projects/name/http';
$b = '/projects/name/http/some/dir';

var_dump(merge_path($a, $b));

function merge_path($path1, $path2)
{
    $p1 = explode('/', trim($path1,' /'));
    $p2 = explode('/', trim($path2,' /'));

    $len = count($p1);

    do
    {
        if (array_slice($p1, -$len) === array_slice($p2, 0, $len))
        {
            return '/'
                 . implode('/', array_slice($p1, 0, -$len))
                 . '/'
                 . implode('/', $p2);
        }
    }
    while (--$len);

    return false;
}