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当状态为引发异常的错误(如400)时,如何读取pythonurllib上的响应体?

urllib python

Ciro Santilli OurBigBook.com · 技术社区 · 6 年前

urllib 创建一个版本,但我犯了一些错误,它失败了一个例外:

Traceback (most recent call last):
  File "./a.py", line 27, in <module>
    'Authorization': 'token ' + token,
  File "/usr/lib/python3.6/urllib/request.py", line 223, in urlopen
    return opener.open(url, data, timeout)
  File "/usr/lib/python3.6/urllib/request.py", line 532, in open
    response = meth(req, response)
  File "/usr/lib/python3.6/urllib/request.py", line 642, in http_response
    'http', request, response, code, msg, hdrs)
  File "/usr/lib/python3.6/urllib/request.py", line 570, in error
    return self._call_chain(*args)
  File "/usr/lib/python3.6/urllib/request.py", line 504, in _call_chain
    result = func(*args)
  File "/usr/lib/python3.6/urllib/request.py", line 650, in http_error_default
    raise HTTPError(req.full_url, code, msg, hdrs, fp)
urllib.error.HTTPError: HTTP Error 422: Unprocessable Entity

不过,GitHub很不错,它解释了为什么在响应主体上失败,如所示: 400 vs 422 response to POST of data

那么,我该如何解读回应体呢?有没有办法防止引发异常?

我尝试捕捉异常并在中进行探索 ipdb ,它给出了一个类型为 urllib.error.HTTPError 但我在那里找不到尸体数据,只有头。

剧本:

#!/usr/bin/env python3

import json
import os
import sys

from urllib.parse import urlencode
from urllib.request import Request, urlopen

repo = sys.argv[1]
tag = sys.argv[2]
upload_file = sys.argv[3]

token = os.environ['GITHUB_TOKEN']
url_template = 'https://{}.github.com/repos/' + repo + '/releases'

# Create.
_json = json.loads(urlopen(Request(
    url_template.format('api'),
    json.dumps({
        'tag_namezxcvxzcv': tag,
        'name': tag,
        'prerelease': True,
    }).encode(),
    headers={
        'Accept': 'application/vnd.github.v3+json',
        'Authorization': 'token ' + token,
    },
)).read().decode())
# This is not the tag, but rather some database integer identifier.
release_id = _json['id']

用法: Can someone give a python requests example of uploading a release asset in github?

1 回复 | 直到 6 年前

Will Keeling 5 年前

这个 HTTPError 有一个 read() 方法,该方法允许您读取响应主体。因此,在您的情况下,您应该能够做一些事情,例如:

try:
    body = urlopen(Request(
        url_template.format('api'),
        json.dumps({
            'tag_namezxcvxzcv': tag,
            'name': tag,
            'prerelease': True,
        }).encode(),
        headers={
            'Accept': 'application/vnd.github.v3+json',
            'Authorization': 'token ' + token,
        },
    )).read().decode()
except urllib.error.HTTPError as e:
    body = e.read().decode()  # Read the body of the error response

_json = json.loads(body)

The docs HTTPError错误