Oracle SQL如何去哪里(A和B)

有没有办法用甲骨文写不(a和B)?

WITH intermediate AS (
    SELECT
        TO_DATE(start_date, 'YYYY-MM-DD') start_date,
        TO_DATE(end_date, 'YYYY-MM-DD') end_date,
        TO_DATE(start_date, 'YYYY-MM-DD') - LAG(TO_DATE(start_date, 'YYYY-MM-DD')) OVER (ORDER BY Start_Date) SLAG,
        LEAD(TO_DATE(end_date, 'YYYY-MM-DD'))OVER (ORDER BY Start_Date) - TO_DATE(end_date, 'YYYY-MM-DD') ELEAD
    FROM
        Projects
    ORDER BY 
        start_date
)
SELECT * 
FROM 
    intermediate i
WHERE 
    NOT (i.SLAG == 1 AND i.ELEAD == 1)
;

非(i.laff==1和i.ELEAD==1) *
第16行出错:
ORA-00936:表达缺失