对于循环-我只能输入1个整数

你的主要问题是,你没有设置 isint .但你无论如何都不应该,因为你已经在 try 块因此,如果你达到了这个代码,它必然是一个 int .2其他一些小事情是,我在运行Python 3,因为它是14年前发布的,所以 raw_input 是 input ,养成用 [] 而不是 list() .它有时更快,但从不慢下来。

以下是工作代码:

import sys

target_int = input("How many integers?")

try:
    target_int = int(target_int)
except ValueError:
    sys.exit("You must enter an integer")

ints = []

count = 0

while count < target_int:
    new_int = input("Please enter integer {0}:".format(count + 1))
    try:
        new_int = int(new_int)
    except ValueError:
        print("You must enter an integer")
        continue # so it doesn't try to append

    # No need to check isint. It is.
    ints.append(new_int)
    count += 1

print("Using a for loop")
for value in ints:
    print(str(value))

另一个小的改进是避免 count 总之,因为它总是 ints 已经

import sys

target_int = input("How many integers?")

try:
    target_int = int(target_int)
except ValueError:
    sys.exit("You must enter an integer")

ints = []

while len(ints) < target_int:
    new_int = input("Please enter integer {0}:".format(len(ints) + 1))
    try:
        ints.append(int(new_int))
    except ValueError:
        print("You must enter an integer")


print("Using a for loop")
for value in ints:
    print(str(value))