C++中的“滤波”高阶函数

包括 <functional> std::not1 cont.erase (std::remove_if (cont.begin (), cont.end (), std::not1 (pred ())), cont.end ());

有一个等效的过滤器 Boost.Range

#include <vector>
#include <boost/lambda/lambda.hpp>
#include <boost/range/algorithm_ext/push_back.hpp>
#include <boost/range/adaptor/filtered.hpp>

using namespace boost::adaptors;
using namespace boost::lambda;

int main()
{
    std::vector<int> v = {3, 2, 6, 10, 5, 2, 45, 3, 7, 66};
    std::vector<int> v2;
    int dist = 5;

    boost::push_back(v2, filter(v, _1 > dist));
    return 0;
}

filter_iterator .

比如说,你有一个自然数的向量,还有一个你想应用到一对迭代器上的函数,它应该只看到过滤后的向量,只有奇数:

#include <algorithm>
#include <vector>
#include <iterator>
#include <numeric>
#include <iostream>
#include <boost/iterator/filter_iterator.hpp>
template<typename Iter>
void do_stuff(Iter beg, Iter end)
{
    typedef typename std::iterator_traits<Iter>::value_type value_t;
    copy(beg, end, std::ostream_iterator<value_t>(std::cout, " "));
    std::cout << '\n';
}
struct is_even {
        bool operator()(unsigned int i) const { return i%2 == 0; }
};
int main()
{
        std::vector<unsigned int> v(10, 1);
        std::partial_sum(v.begin(), v.end(), v.begin()); // poor man's std::iota()

        // this will print all 10 numbers
        do_stuff(v.begin(), v.end());
        // this will print just the evens
        do_stuff(boost::make_filter_iterator<is_even>(v.begin(), v.end()),
                 boost::make_filter_iterator<is_even>(v.end(), v.end()));

}

使用 remove_if 或 remove_copy_if ,与 not1 (定义见 <functional> )反转谓词。像这样:

#include <algorithm>
#include <functional>

template <class ForwardIterator, class Predicate>
ForwardIterator filter(ForwardIterator first, ForwardIterator last, 
                       Predicate pred)
{
    return std::remove_if(first, last, std::not1(pred));
}

template <class InputIterator, class OutputIterator, class Predicate>
OutputIterator filter_copy(InputIterator first, InputIterator last, 
                           OutputIterator result, Predicate pred)
{
    return std::remove_copy_if(first, last, result, std::not1(pred));
}