代码之家 › 专栏 › 技术社区 › Somename

如何在StackNavigator中将参数传递到屏幕?

react-navigation react-native

Somename · 技术社区 · 7 年前

我的本地代码:

import React, { Component } from 'react';
import { AppRegistry, ActivityIndicator, StyleSheet, ListView, 
  Text, Button, TouchableHighlight, View } from 'react-native';

import { StackNavigator } from 'react-navigation';
import DetailsPage from './src/screens/DetailsPage';

class HomeScreen extends React.Component {

   constructor() {
    super();
    const ds = new ListView.DataSource({rowHasChanged: (r1, r2) => r1 !== r2});
    this.state = {
      userDataSource: ds,
    };
  }

  componentDidMount(){
      this.fetchUsers();
  }

    fetchUsers(){

        fetch('https://jsonplaceholder.typicode.com/users')
            .then((response) => response.json())
            .then((response) => {
                this.setState({
                    userDataSource: this.state.userDataSource.cloneWithRows(response)
                });
            });
    }

    onPress(user){
        this.props.navigator.push({
            id: 'DetailPage'
        });
    }

  renderRow(user, sectionID, rowID, highlightRow){
      return(
      <TouchableHighlight onPress={()=>{this.onPress(user)} } >
      <View style={styles.row}>
        <Text style={styles.rowText}> {user.name} </Text>

      </View>
      </TouchableHighlight>
      )
  }


  render(){
      return(
          <ListView
            dataSource = {this.state.userDataSource}
            renderRow = {this.renderRow.bind(this)}
          />
      )
  } 
}

const NavigationTest = StackNavigator({
  Home: { screen: HomeScreen },
  DetailsPage: { screen: DetailsPage },
});

详细信息屏幕为:

import React, { Component } from 'react';
import { StyleSheet, Text, View } from 'react-native';

import styles from '../styles';


export default class DetailsPage extends React.Component {
  static navigationOptions = ({ navigation }) => ({
    title: `User: ${navigation.state.params.user.name}`,
  });
  render() {
    const { params } = this.props.navigation.state;
    return (
      <View>
        <Text style={styles.myStyle}>Name: {params.name}</Text>
        <Text style={styles.myStyle}>Email: {params.email}</Text>
      </View>
    );
  }
}

我不能通过考试 user DetailsPage 代码为:

onPress(user){
        this.props.navigator.push({
            id: 'DetailPage'
        });
    }

我想导航到 DetailPage onPress 作用如果我像这样提醒它:

onPress(user){ Alert.alert(user.name)}

非常感谢!

8 回复 | 直到 7 年前

125

jjjjjjjjjjjjjjjjjjjj 2 年前

您可以使用 navigate

onPress(user) {
  this.props.navigation.navigate(
    'DetailPage',
    { user },
  );
}

反应导航5.x,6.x(2022)

在中访问它们 this.props.route.params 。例如 DetailsPage

<Text style={styles.myStyle}>{this.props.route.params.user.name}</Text>

https://reactnavigation.org/docs/params/

反应导航<=4.x

在中访问它们 this.props.navigation.state.params 详细信息页面

<Text style={styles.myStyle}>{this.props.navigation.state.params.user.name}</Text>

https://reactnavigation.org/docs/4.x/params/

Aurangzaib Rana 5 年前

在react钩子中,参数使用useNavigation发送导航

import { useNavigation } from '@react-navigation/native';

const navigation = useNavigation();

<Button
      title="Back"
      onPress={() => {
        navigation.navigate('MyScreen',{name:'test'});
      }}
    />

function MyScreen() {
  const name = useNavigationParam('name');
  return <p>name is {name}</p>;
}

4b0 Agit 4 年前

See this .

它解决了我的问题。

this.props.navigation.navigate("**stack_Name**", {
 screen:"screen_name_connect_with_**stack_name**",
 params:{
 user:"anything_string_or_object"
}
})

Dharman Aman Gojariya 4 年前

const CountriesList = ({ navigation }) => {

/* Function to navigate to 2nd screen */
  const viewCountry = (country) => {
    navigation.navigate('ListItemPageRoute', { name: country.country_name });
  };
}

对于第二个页面名,请说ListItemPageRoute

const ListItemPageRoute = (props) => {

return (
    <View style={styles.container}>
        <Text style={styles.countryText}> { props.route.params.name } </Text>
    </View>
  );
};

'道具。“路由”对象将包含您希望从一个屏幕传递到另一个屏幕的所有参数的列表。

rubal islam 4 年前

对于功能部件:

import * as React from 'react';
import { Button } from 'react-native';
import { useNavigation } from '@react-navigation/native';

function MyBackButton() {
  const navigation = useNavigation();

  return (
    <Button
      title="Back"
      onPress={() => {
        navigation.goBack();
      }}
    />
  );
}

class MyText extends React.Component {
  render() {
    // Get it from props
    const { route } = this.props;
  }
}

// Wrap and export
export default function(props) {
  const route = useRoute();

  return <MyText {...props} route={route} />;
}

Hamza Ishfaq 4 年前

onPress={()=>{this.props.navigation.navigate('AllImages',{Types:item.type}}) 控制台.log('值 强文本 ,this.props.route.params.Types)**

Muhammad Haidar 4 年前

onPress={(item)=>props.navigation.navigate('你的屏幕名',{item:item})}

2) 如何在另一个屏幕上获取数据: 常量{item}=props.route.params

-1

KAYZORK 3 年前

export default () => {
  
  const MainScreenComponent = ({navigation}) => (
    <MainScreen
      navigation={navigation}
      /**
      *
      * And here your parameters...
      *
      */
    />
  );

  const HomeScreenComponent = ({navigation}) => (
    <HomeScreen
      navigation={navigation}
      /**
      *
      * And here your parameters...
      *
      */
    />
  );

  return (
    <NavigationContainer>
      <Stack.Navigator initialRouteName="MainScreen">
        <Stack.Screen name="MainScreen" component={MainScreenComponent}/>
        <Stack.Screen name="HomeScreen" component={MomeScreenComponent}/>
      </Stack.Navigator>
    </NavigationContainer>
  );
};