用字符替换单词中的数字

您可以调整以下示例以满足您的要求:

如果要替换的数字仅位于单词末尾:

import re

s = "Question1: a12 is the number of a, 1b is the number of b, 123"
x = re.compile('\w+').findall(s)
y = [re.sub(r'(?<=[a-zA-Z])\d+$', '$', w) for w in x]
print(y)

输出:

['Question$', 'a$', 'is', 'the', 'number', 'of', 'a', '1b', 'is', 'the', 'number', 'of', 'b', '123']

在 (结果为字符串形式):

import re
s ="Question1: a12 is the number of a, 1b is the number of b, abc1uvf"
pat = re.compile(r'(?<=[a-zA-Z])\d+(?=\W)')
print(re.sub(pat, "$", s))

输出:

Question$: a$ is the number of a, 1b is the number of b, abc1uvf

如果数字可以位于单词中的任何位置,请使用:

import re

s = "Question1: a12 is the number of a, 1b is the number of b, 123"
x = re.compile('\w+').findall(s)
y = [re.sub(r'\d+', '$', w) for w in x]
print(y)

输出:

['Question$', 'a$', 'is', 'the', 'number', 'of', 'a', '$b', 'is', 'the', 'number', 'of', 'b', '$']

123 被替换为 $ ,如果这不是您想要的用途:

import re

s = "Question1: a12 is the number of a, 1b is the number of b, 123"
x = re.compile('\w+').findall(s)
y = [re.sub(r'(?<=[a-zA-Z])\d+|\d+(?=[a-zA-Z])', '$', w) for w in x]
print(y)

['Question$', 'a$', 'is', 'the', 'number', 'of', 'a', '$b', 'is', 'the', 'number', 'of', 'b', '123']

一步到位:

import re

s = "Question1: a12 is the number of a, 1b is the number of b, 123"
y = re.sub(r'(?<=[a-zA-Z])\d+|\d+(?=[a-zA-Z])', '$', s)
print(y)

试试这个:

import re
s ="Question1: a12 is the number of a, 1b is the number of b"
pat = re.compile("[0-9]+")
print(re.sub(pat, "$", s))

试试这个:

import re
x = ['Question1', 'a12', 'is', 'the', 'number', 'of', 'a', '1b', 'is', 'the', 'number', 'of', 'b']
y = [re.sub(r'\d+', '$', w) for w in x]
print(y)

['Question$', 'a$', 'is', 'the', 'number', 'of', 'a', '$b', 'is', 'the', 'number', 'of', 'b']

说明:

• re.sub 是要替换的数字。

  \d+ 找到数字, + 代表一个或多个事件

• 第二个参数采用什么来替换模式。在这种情况下 它的 '$'

• 第三个参数接受输入字符串。

这是你想要的:

import re
s ="Question1: a12 is the number of a, 1b is the number of b"
print(re.sub('\d+', '$', s))

输出:

Question$: a$ is the number of a, $b is the number of b