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mysql-基于另一组列(文本)计算列(2列带数字)

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  • Himal Bissessar  · 技术社区  · 7 年前

    您好,我想查找以下内容的查询,我正在尝试计算两列之间的数据,但基于另一列,该列需要是选定的具有相同值的组

    未过滤

    开始时间\uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu

    12:

    10: 59:00.3 \uuuuuuuuuuuuuuuu11:03:03.3 \uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu2.2.2

    19: 59:00.3 \uuuuuuuuuuuuuuu20:02:03.3 \uuuuuuuuuuuuuuuuuuuuuuuuuuu1.1.1

    已筛选

    开始时间\uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu

    12:

    19: 59:00.3 \uuuuuuuuuuuuuuu20:02:03.3 \uuuuuuuuuuuuuuuuuuuuuuuuuuu1.1.1

    如果您看到上表,我只想要所选的IP,即1.1.1.1,然后从那里计算该出口IP从开始时间到断开连接时间的总持续时间。

    所以第3列有多个值,但是我需要选择相同的值,然后根据第3列计算第1列和第2列的总和。

    如果您有什么想法,请告诉我,因为我尝试了多个查询,但无法得到正确的查询

    1 回复  |  直到 7 年前
        1
  •  0
  •   Emad Elpurgy    7 年前

    计算到次之间的差值。 可以使用time\u to\u sec将每个时间值转换为秒 从结束时间中减去开始时间,得到以秒为单位的时间段。 您可以使用SEC\u to\u time将其转换回时间格式 实例

    select
    column3,
    SEC_TO_TIME(sum(TIME_TO_SEC(column2) - TIME_TO_SEC(column1))
    from 
    table 
    group by column3