python popen命令。等待命令完成

根据脚本的工作方式,有两个选项。如果您希望命令在执行时阻塞,而不执行任何操作,则只需使用 subprocess.call .

#start and block until done
subprocess.call([data["om_points"], ">", diz['d']+"/points.xml"])

如果你想在执行的时候做一些事情,或者把事情反馈给 stdin ,你可以使用 communicate 后 popen 打电话。

#start and process things, then wait
p = subprocess.Popen([data["om_points"], ">", diz['d']+"/points.xml"])
print "Happens while running"
p.communicate() #now wait plus that you can send commands to process

如文件所述, wait 会死锁,所以通信是明智的。

你可以使用 subprocess 为了达到这个目的。

import subprocess

#This command could have multiple commands separated by a new line \n
some_command = "export PATH=$PATH://server.sample.mo/app/bin \n customupload abc.txt"

p = subprocess.Popen(some_command, stdout=subprocess.PIPE, shell=True)

(output, err) = p.communicate()  

#This makes the wait possible
p_status = p.wait()

#This will give you the output of the command being executed
print "Command output: " + output

你要找的是 wait 方法。

wait() 对我来说很好。子流程p1、p2和p3同时执行。因此,所有进程都在3秒后完成。

import subprocess

processes = []

p1 = subprocess.Popen("sleep 3", stdout=subprocess.PIPE, shell=True)
p2 = subprocess.Popen("sleep 3", stdout=subprocess.PIPE, shell=True)
p3 = subprocess.Popen("sleep 3", stdout=subprocess.PIPE, shell=True)

processes.append(p1)
processes.append(p2)
processes.append(p3)

for p in processes:
    if p.wait() != 0:
        print("There was an error")

print("all processed finished")

让你试图传递的命令

os.system('x')

然后你把它藏起来

t = os.system('x')

现在,python将等待命令行的输出,以便将其分配给变量 t .