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如何显示给定周数的格式化工作日[已关闭]

strtotime php

-2

ilp · 技术社区 · 12 年前

我使用下面的php获取给定周数和年份的工作日:

$week_number = 42; 
$year = 2014; 
for($day = 1; $day<=7; $day++)
   {
     echo date('m/d/Y',strtotime($year."W".          $week_number.$day));
  }

输出的外观如下所示:

我怎样才能让它看起来像这样:

 Oct 13 - Oct 19.

非常感谢。

4 回复 | 直到 12 年前

svennergr 12 年前

<?php

$week_number = 42; 
$year = 2014; 
echo date('M d',strtotime($year."W".$week_number . 1)) . " - " . date('M d',strtotime($year."W".$week_number . 7)).".";
?>

Mihai Iorga 12 年前

$week_number = 42; 
$year = 2014; 

$week_number = ($week_number < 10) ? '0'.$week_number : $week_number;
echo date('M d',strtotime($year.'W'.$week_number.'1')).' - '.date('M d',strtotime($year.'W'.$week_number.'7')).'.';

// remember that $week_number must be prefixed with 0 if week number is lower than 10