从外部api反序列化JSON数据并返回更精简的JSON数据

我正在练习web api。我的目标是创建一个Get端点,它从外部api接收数据,然后返回一个更精简的结果。 外部api链接: https://www.themealdb.com/api/json/v1/1/search.php?f=a , 外部api数据如下所示:

{
  "meals": [
    {
      "idMeal": "52768",
      "strMeal": "Apple Frangipan Tart",
      "strDrinkAlternate": null,
      "strCategory": "Dessert",
      .....
    },
    {
      "idMeal": "52893",
      "strMeal": "Apple & Blackberry Crumble",
      ....
     }
   ]
}

我希望我的端点提供更精简的结果,如下所示:

[
    {
      "idMeal": "52768",
      "strMeal": "Apple Frangipan Tart"
    },
    {
      "idMeal": "52893",
      "strMeal": "Apple & Blackberry Crumble"
     }
 ] 

以下代码是我到目前为止尝试的代码,结果为空。。我希望我没有偏离正确的道路太远。谢谢

using System.Text.Json;
using System.Text.Json.Serialization;
using Microsoft.AspNetCore.Mvc;
using RestSharp;

namespace testAPI.Controllers;
public class Content
{
    public List<Meal> Meals { get; set; }
}

public class Meal
{
    [JsonPropertyName("idMeal")]
    public string MealId { get; set; }
    [JsonPropertyName("strMeal")]
    public string Name { get; set; }
}

[ApiController]
[Route("api/[controller]")]
public class DishesController : ControllerBase
{
    
    [HttpGet]
    public async Task<IActionResult> GetAllRecipes()
    {
        var client = new RestClient($"https://www.themealdb.com/api/json/v1/1/search.php?f=a");
        var request = new RestRequest();
        var response = await client.ExecuteAsync(request);
        var mealList = JsonSerializer.Deserialize<Content>(response.Content);
        var result = JsonSerializer.Serialize(mealList.Meals);
        
        return Ok(result);
    }