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如何通过将setter函数传递给jitclass本身来用它的字符串名更新jitclass变量?

numba python

ymmx · 技术社区 · 4 年前

我正在寻找一种方法来修改 jitclass 名称为字符串的变量。我试图编写setter和getter函数( get_A 和 set_A ),我得到的方法是 jitclass公司

numba.errors.TypingError: Failed in nopython mode pipeline (step: nopython frontend)
non-precise type pyobject
[1] During: typing of argument at <string> (3)

File "<string>", line 3:
<source missing, REPL/exec in use?>

This error may have been caused by the following argument(s):
- argument 1: cannot determine Numba type of <class 'tuple'>

下面是最简单的例子:

from numba import jitclass, int32, float64

spec = [('A' ,float64),('B' ,float64),('C' ,float64)]

@jitclass(spec)
class maClass():
    def __init__(self,):
        self.A = 0.

    def get_A(self):
        return self.A

    def set_A(self, x):
        self.A = x

    def update(self, func, val):
        func(val)

C1 = maClass()
print('A',C1.A)

Names= ['A']
vals= [1.]

func = getattr(C1,'set_'+Names[0])
print(func)

C1.update(func,vals[0])
print('A',C1.A)

0 回复 | 直到 4 年前

ymmx 4 年前

这是我想出的解决办法。

def get_Variable_Names():
    return ['A','B','C']

get_Variable_Names

def update_val(self, i, var):
    if i == 0:
        self.A = var
    elif i == 1:
        self.B = var
    elif i == 2:
        self.C = var

为了使用这个函数,我在由返回的列表中搜索变量名的索引 获取变量名 然后打电话给 update_val jitclass的函数。

listnames = get_Variable_Names()
val = 1.
name = 'A'
index = listnames.index(name)
C1.update_val(index,val)

这是所有的密码。

来自numba import jitclass,int32,float64

def get_Variable_Names():
    return ['A','B','C']

spec = [('A' ,float64),('B' ,float64),('C' ,float64)]

@jitclass(spec)
class maClass():
    def __init__(self,):
        self.A = 0.
        self.B = 0.
        self.C = 0.

    def update_val(self, i, var):
        if i == 0:
            self.A = var
        elif i == 1:
            self.B = var
        elif i == 2:
            self.C = var

C1 = maClass()
listnames = get_Variable_Names()
val = 1.
name = 'A'
index = listnames.index(name)
C1.update_val(index,val)

val = 2.
name = 'B'
index = listnames.index(name)
C1.update_val(index,val)

val = 3.
name = 'C'
index = listnames.index(name)
C1.update_val(index,val)
print('A',C1.A)
print('B',C1.B)
print('C',C1.C)

它不是我一直在找的,但现在已经找到了。

listnames= ['A','B','C']

for i, n in enumerate(listnames):
    if i == 0:
        print('if i == ' + str(i)+ ' :\n\tself.' + n + ' = var')
    else:
        print('elif i == ' + str(i) + ' :\n\tself.' + n + ' = var')