抽象类有选择地公开基于派生类型的方法

我正在编写一个实现工厂的程序 TimeManager 生成两种类型的对象;一 Timer 和a StopWatch . 这两个对象都派生自抽象类 TimePiece ,并共享常用方法。我希望工厂返回类型 计时器 ,但因为 计时器 我不能实现额外的方法。我怎样才能 计时器 暴露 计时器 的额外方法,而不将其暴露于 秒表 何时创建这些各自的类型?我希望这是有意义的,因为这有点难以解释。

时间管理器。h类

enum TimePieceType{TIMER, STOP_WATCH};

class TimeManager {
public:
    TimeManager();
    ~TimeManager();

    void Tick();
    TimePiece* AddTimePiece(TimePieceType timeType);
};

计时器。h类

enum RunningState { STOPPED, RUNNING, PAUSED };

class TimePiece {
private:
    unsigned long startTime = 0;
    unsigned long currentTime = 0;
    unsigned long pauseOffset = 0;

protected:
    Time time;
    RunningState state = STOPPED;

public:
    TimePiece() = default;
    virtual ~TimePiece() = default;

    void Stop();
    void Start();
    void Pause();
    void Resume();
    void Reset();
    virtual void Tick();

    Time GetTime();
    RunningState GetState();
    virtual uint8_t GetId() = 0;
};

秒表h类

class StopWatch : public TimePiece {
private:
    uint8_t watchId = 0;
    static int8_t currentId;
    
public:
    StopWatch();
    virtual ~StopWatch();

    uint8_t GetId();
};

计时器。h类

class Timer : public TimePiece {
private:
    uint8_t timerId = 0;
    static int8_t currentId;
    unsigned long timeout;

public:
    Timer();
    ~Timer();

    void Tick() override;

    void SetTimeoutMs(unsigned long timeout);
    void SetTimeoutSec(unsigned long timeout);

    uint8_t GetId();
    Time GetRemainingTime();
    unsigned long GetTimeout();
};