当随机列表返回空时,如何使用itertools和fillvalue压缩生成的列表?

import grequests
import json
import time
import itertools

urls3 = [
        #'https://api.livecoin.net/exchange/order_book?currencyPair=RBIES/BTC&depth=5',
        'https://api.livecoin.net/exchange/order_book?currencyPair=REE/BTC&depth=5',
        #'https://api.livecoin.net/exchange/order_book?currencyPair=RLT/BTC&depth=5',
]
requests = (grequests.get(u) for u in urls3)
responses = grequests.map(requests)
#CellRange("B28:DJ48").clear()
def make_column(catalog_response, name):
        column = []
        catalog1 = list(itertools.izip_longest(catalog_response.json()[name][0:5], fillvalue='0 '))
        #catalog1 = catalog_response.json()[name][0:5]
        print(catalog1)
        #quantities1, rates1 = list(itertools.izip_longest(*catalog1,fillvalue='0.0001'))    #uncomment for print #2
        #quantities1, rates1 = zip(*catalog1)    #uncomment for print #2
        print(quantities1)

打印输出 catalog1 因为只有第二个链接会产生以下输出:

[]
[([u'0.00000001', u'9907729.00000000'],), ([u'0.00000001', u'44800.00000000'],), ([u'0.00000002', u'8463566.49169284'],), ([u'0.00000002', u'3185222.59932121'],), ([u'0.00000002', u'25000.00000000'],)]

如您所见,第一个阵列打印 []

import itertools

list1 = ['a', 'b', 'c', 'd', 'e']
list2 = []

print list(itertools.izip_longest(list1,list2, fillvalue='0'))

该输出如下:

[('a', '0'), ('b', '0'), ('c', '0'), ('d', '0'), ('e', '0')]

我想也许是跑步

    `column = []
    catalog1 = list(itertools.izip_longest(catalog_response.json()[name][0:5], fillvalue='0 '))
    #catalog1 = catalog_response.json()[name][0:5]
    #print(catalog1)
    quantities1, rates1 = list(itertools.izip_longest(*catalog1,fillvalue='0'))    #uncomment for print #2
    #quantities1, rates1 = zip(*catalog1)    #uncomment for print #2
    print(quantities1)`

可能会解决问题。但它返回以下错误: ValueError: need more than 0 values to unpack

How do I get my DataNitro table to either skip over failed iterations or print none to the table? 但我觉得这两个问题虽然有着相同的目的,但却是截然不同的。