如何用groovy的XML Slurper更新XML?

我目前能想到的克隆节点的唯一方法是将它们序列化为文本,并将它们解析为新的xml位

就像这样:

import groovy.xml.StreamingMarkupBuilder
import groovy.xml.XmlUtil

def xml = """
<customer>
  <address>
    <street />
    <city />
    <postalcode />
  </address>
</customer>
"""

def root = new XmlSlurper().parseText( xml )
2.times {
  String addressXml = new StreamingMarkupBuilder().bindNode( root.address )
  clonedAddress = new XmlSlurper().parseText( addressXml )
  root.appendNode( clonedAddress )
}

println XmlUtil.serialize( root )

打印出来的是:

<?xml version="1.0" encoding="UTF-8"?>
<customer>
  <address>
    <street/>
    <city/>
    <postalcode/>
  </address>
  <address>
    <street/>
    <city/>
    <postalcode/>
  </address>
  <address>
    <street/>
    <city/>
    <postalcode/>
  </address>
</customer>

可能有一种更简洁的方法…但目前,我的头脑是一片空白。。。

GPathResult.replaceBody()

http://www.javamonamour.org/2011/11/groovy-modifying-xml-with-xmlslurper.html