使用专用的ELF部分“收集”数据结构。
例如,在中定义数据结构
信息h
作为
#ifndef INFO_H
#define INFO_H
#ifndef INFO_ALIGNMENT
#if defined(__LP64__)
#define INFO_ALIGNMENT 16
#else
#define INFO_ALIGNMENT 8
#endif
#endif
struct info {
long key;
long val;
} __attribute__((__aligned__(INFO_ALIGNMENT)));
#define INFO_NAME(counter) INFO_CAT(info_, counter)
#define INFO_CAT(a, b) INFO_DUMMY() a ## b
#define INFO_DUMMY()
#define DEFINE_INFO(data...) \
static struct info INFO_NAME(__COUNTER__) \
__attribute__((__used__, __section__("info"))) \
= { data }
#endif /* INFO_H */
这个
INFO_ALIGNMENT
宏是
链接器
将每个符号单独放置到
info
第节。C编译器同意这一点很重要,否则不能将节内容视为数组。(你会得到一个不正确的结构数量,只有第一个(加上每N'th)是正确的,其余的结构都会混乱。实际上,C编译器和链接器在“array”部分中的每个结构的大小上存在分歧。
请注意,可以添加预处理器宏来微调
信息对齐
对于您使用的每个体系结构,您也可以在编译时覆盖它,例如在makefile中。(对于GCC,供应
-DINFO_ALIGNMENT=32
例如。)
这个
used
属性确保在对象文件中发出定义,即使在同一数据文件中没有以其他方式引用该定义。这个
section("info")
属性将数据放入
信息
对象文件中的节。分区名称(
信息
)由你决定。
这些都是关键部分,否则完全取决于您如何定义宏,或者是否定义宏。使用宏很容易,因为不需要担心为结构使用唯一的变量名。此外,如果至少指定了一个成员,则所有其他成员都将初始化为零。
在源文件中,将数据对象定义为
#include "info.h"
/* Suggested, easy way */
DEFINE_INFO(.key = 5, .val = 42);
/* Alternative way, without relying on any macros */
static struct info foo __attribute__((__used__, __section__("info"))) = {
.key = 2,
.val = 1
};
链接器提供符号
__start_info
和
__stop_info
,以获取
信息
第节。在你的
主C
,例如使用
#include "info.h"
extern struct info __start_info[];
extern struct info __stop_info[];
#define NUM_INFO ((size_t)(__stop_info - __start_info))
#define INFO(i) ((__start_info) + (i))
所以你可以枚举所有的信息结构。例如,
int main(void)
{
size_t i;
printf("There are %zu info structures:\n", NUM_INFO);
for (i = 0; i < NUM_INFO; i++)
printf(" %zu. key=%ld, val=%ld\n", i,
__start_info[i].key, INFO(i)->val);
return EXIT_SUCCESS;
}
为了举例说明,我使用了
__start_info[]
阵列访问(显然可以
#define SOMENAME __start_info
如果你想,只要确保你不使用
SOMENAME
在main.c的其他地方,所以你可以使用
SOMENAME[]
作为数组),以及
INFO()
宏。
让我们来看一个实际的例子,一个RPN计算器。
我们使用分区
ops
要定义操作,请使用中定义的设施
哦!
:
#ifndef OPS_H
#define OPS_H
#include <stdlib.h>
#include <errno.h>
#ifndef ALIGN_SECTION
#if defined(__LP64__) || defined(_LP64)
#define ALIGN_SECTION __attribute__((__aligned__(16)))
#elif defined(__ILP32__) || defined(_ILP32)
#define ALIGN_SECTION __attribute__((__aligned__(8)))
#else
#define ALIGN_SECTION
#endif
#endif
typedef struct {
size_t maxsize; /* Number of values allocated for */
size_t size; /* Number of values in stack */
double *value; /* Values, oldest first */
} stack;
#define STACK_INITIALIZER { 0, 0, NULL }
struct op {
const char *name; /* Operation name */
const char *desc; /* Description */
int (*func)(stack *); /* Implementation */
} ALIGN_SECTION;
#define OPS_NAME(counter) OPS_CAT(op_, counter, _struct)
#define OPS_CAT(a, b, c) OPS_DUMMY() a ## b ## c
#define OPS_DUMMY()
#define DEFINE_OP(name, func, desc) \
static struct op OPS_NAME(__COUNTER__) \
__attribute__((__used__, __section__("ops"))) = { name, desc, func }
static inline int stack_has(stack *st, const size_t num)
{
if (!st)
return EINVAL;
if (st->size < num)
return ENOENT;
return 0;
}
static inline int stack_pop(stack *st, double *to)
{
if (!st)
return EINVAL;
if (st->size < 1)
return ENOENT;
st->size--;
if (to)
*to = st->value[st->size];
return 0;
}
static inline int stack_push(stack *st, double val)
{
if (!st)
return EINVAL;
if (st->size >= st->maxsize) {
const size_t maxsize = (st->size | 127) + 129;
double *value;
value = realloc(st->value, maxsize * sizeof (double));
if (!value)
return ENOMEM;
st->maxsize = maxsize;
st->value = value;
}
st->value[st->size++] = val;
return 0;
}
#endif /* OPS_H */
基本操作集在
操作基本.c
:
#include "ops.h"
static int do_neg(stack *st)
{
double temp;
int retval;
retval = stack_pop(st, &temp);
if (retval)
return retval;
return stack_push(st, -temp);
}
static int do_add(stack *st)
{
int retval;
retval = stack_has(st, 2);
if (retval)
return retval;
st->value[st->size - 2] = st->value[st->size - 1] + st->value[st->size - 2];
st->size--;
return 0;
}
static int do_sub(stack *st)
{
int retval;
retval = stack_has(st, 2);
if (retval)
return retval;
st->value[st->size - 2] = st->value[st->size - 1] - st->value[st->size - 2];
st->size--;
return 0;
}
static int do_mul(stack *st)
{
int retval;
retval = stack_has(st, 2);
if (retval)
return retval;
st->value[st->size - 2] = st->value[st->size - 1] * st->value[st->size - 2];
st->size--;
return 0;
}
static int do_div(stack *st)
{
int retval;
retval = stack_has(st, 2);
if (retval)
return retval;
st->value[st->size - 2] = st->value[st->size - 1] / st->value[st->size - 2];
st->size--;
return 0;
}
DEFINE_OP("neg", do_neg, "Negate current operand");
DEFINE_OP("add", do_add, "Add current and previous operands");
DEFINE_OP("sub", do_sub, "Subtract previous operand from current one");
DEFINE_OP("mul", do_mul, "Multiply previous and current operands");
DEFINE_OP("div", do_div, "Divide current operand by the previous operand");
为了简单起见,计算器希望每个值和操作数都是单独的命令行参数。我们的
主C
包含操作查找、基本用法、值分析和打印结果(或错误):
#include <stdlib.h>
#include <string.h>
#include <stdio.h>
#include <errno.h>
#include "ops.h"
extern struct op __start_ops[];
extern struct op __stop_ops[];
#define NUM_OPS ((size_t)(__stop_ops - __start_ops))
static int do_op(stack *st, const char *opname)
{
struct op *curr_op;
if (!st || !opname)
return EINVAL;
for (curr_op = __start_ops; curr_op < __stop_ops; curr_op++)
if (!strcmp(opname, curr_op->name))
break;
if (curr_op >= __stop_ops)
return ENOTSUP;
return curr_op->func(st);
}
static int usage(const char *argv0)
{
struct op *curr_op;
fprintf(stderr, "\n");
fprintf(stderr, "Usage: %s [ -h | --help ]\n", argv0);
fprintf(stderr, " %s RPN-EXPRESSION\n", argv0);
fprintf(stderr, "\n");
fprintf(stderr, "Where RPN-EXPRESSION is an expression using reverse\n");
fprintf(stderr, "Polish notation, and each argument is a separate value\n");
fprintf(stderr, "or operator. The following operators are supported:\n");
for (curr_op = __start_ops; curr_op < __stop_ops; curr_op++)
fprintf(stderr, "\t%-14s %s\n", curr_op->name, curr_op->desc);
fprintf(stderr, "\n");
return EXIT_SUCCESS;
}
int main(int argc, char *argv[])
{
stack all = STACK_INITIALIZER;
double val;
size_t i;
int arg, err;
char dummy;
if (argc < 2 || !strcmp(argv[1], "-h") || !strcmp(argv[1], "--help"))
return usage(argv[0]);
for (arg = 1; arg < argc; arg++)
if (sscanf(argv[arg], " %lf %c", &val, &dummy) == 1) {
err = stack_push(&all, val);
if (err) {
fprintf(stderr, "Cannot push %s to stack: %s.\n", argv[arg], strerror(err));
return EXIT_FAILURE;
}
} else {
err = do_op(&all, argv[arg]);
if (err == ENOTSUP) {
fprintf(stderr, "%s: Operation not supported.\n", argv[arg]);
return EXIT_FAILURE;
} else
if (err) {
fprintf(stderr, "%s: Cannot perform operation: %s.\n", argv[arg], strerror(err));
return EXIT_FAILURE;
}
}
if (all.size < 1) {
fprintf(stderr, "No result.\n");
return EXIT_FAILURE;
} else
if (all.size > 1) {
fprintf(stderr, "Multiple results:\n");
for (i = 0; i < all.size; i++)
fprintf(stderr, " %.9f\n", all.value[i]);
return EXIT_FAILURE;
}
printf("%.9f\n", all.value[0]);
return EXIT_SUCCESS;
}
请注意,如果有许多操作,那么构造一个哈希表来加快操作查找将非常有意义。
最后,我们需要
生成文件
要将所有这些联系在一起:
CC := gcc
CFLAGS := -Wall -O2 -std=c99
LDFLAGS := -lm
OPS := $(wildcard ops-*.c)
OPSOBJS := $(OPS:%.c=%.o)
PROGS := rpncalc
.PHONY: all clean
all: clean $(PROGS)
clean:
rm -f *.o $(PROGS)
%.o: %.c
$(CC) $(CFLAGS) -c $^
rpncalc: main.o $(OPSOBJS)
$(CC) $(CFLAGS) $^ $(LDFLAGS) -o $@
因为这个论坛不保存
标签
而make需要它们进行缩进,你可能需要在复制粘贴完上面的缩进后进行修复。我用
sed -e 's|^ *|\t|' -i Makefile
如果你编译(
make clean all
)然后跑(
./rpncalc
)上面,您将看到使用信息:
Usage: ./rpncalc [ -h | --help ]
./rpncalc RPN-EXPRESSION
Where RPN-EXPRESSION is an expression using reverse
Polish notation, and each argument is a separate value
or operator. The following operators are supported:
div Divide current operand by the previous operand
mul Multiply previous and current operands
sub Subtract previous operand from current one
add Add current and previous operands
neg Negate current operand
如果你跑步,例如
./rpncalc 3.0 4.0 5.0 sub mul neg
,你得到结果
3.000000000
.
现在,让我们添加一些新的操作,
操作sqrt.c
:
#include <math.h>
#include "ops.h"
static int do_sqrt(stack *st)
{
double temp;
int retval;
retval = stack_pop(st, &temp);
if (retval)
return retval;
return stack_push(st, sqrt(temp));
}
DEFINE_OP("sqrt", do_sqrt, "Take the square root of the current operand");
因为上面的makefile编译了以
ops-
在最后一个二进制文件中,您只需要重新编译源文件:
全部清除
. 正在运行
/rpncalc公司
现在输出
Usage: ./rpncalc [ -h | --help ]
./rpncalc RPN-EXPRESSION
Where RPN-EXPRESSION is an expression using reverse
Polish notation, and each argument is a separate value
or operator. The following operators are supported:
sqrt Take the square root of the current operand
div Divide current operand by the previous operand
mul Multiply previous and current operands
sub Subtract previous operand from current one
add Add current and previous operands
neg Negate current operand
你有了新的
sqrt
操作员可用。
测试,例如
./rpncalc 1 1 1 1 add add add sqrt
产量
2.000000000
,如预期。