代码之家 › 专栏 › 技术社区 › Alin

Android读取文本原始资源文件

resources text android

105

Alin · 技术社区 · 14 年前

事情很简单,但并不像想象的那样。

b) 如果适用法律要求对软件,所有这些保证自交货之日起天。

(c) 无口头或书面信息或其经销商、分销商、代理商或员工应创建担保或以任何方式增加任何

(d) (仅限美国)有些州没有允许排除隐含的不适用于你。本保证提供还有其他合法权利

在我的屏幕上有这样一个布局:

<LinearLayout  xmlns:android="http://schemas.android.com/apk/res/android"
                     android:layout_width="fill_parent" 
                     android:layout_height="wrap_content" 
                     android:gravity="center" 
                     android:layout_weight="1.0"
                     android:layout_below="@+id/logoLayout"
                     android:background="@drawable/list_background"> 

            <ScrollView android:layout_width="fill_parent"
                        android:layout_height="fill_parent">

                    <TextView  android:id="@+id/txtRawResource" 
                               android:layout_width="fill_parent" 
                               android:layout_height="fill_parent"
                               android:padding="3dip"/>
            </ScrollView>  

    </LinearLayout>

读取原始资源的代码是:

TextView txtRawResource= (TextView)findViewById(R.id.txtRawResource);

txtDisclaimer.setText(Utils.readRawTextFile(ctx, R.raw.rawtextsample);

public static String readRawTextFile(Context ctx, int resId)
{
    InputStream inputStream = ctx.getResources().openRawResource(resId);

    ByteArrayOutputStream byteArrayOutputStream = new ByteArrayOutputStream();

    int i;
    try {
        i = inputStream.read();
        while (i != -1)
        {
            byteArrayOutputStream.write(i);
            i = inputStream.read();
        }
        inputStream.close();
    } catch (IOException e) {
        return null;
    }
    return byteArrayOutputStream.toString();
}

显示了文本get,但每行之后我都得到一个奇怪的字符[]如何删除该字符?我想是新线。

工作溶液

public static String readRawTextFile(Context ctx, int resId)
{
    InputStream inputStream = ctx.getResources().openRawResource(resId);

    InputStreamReader inputreader = new InputStreamReader(inputStream);
    BufferedReader buffreader = new BufferedReader(inputreader);
    String line;
    StringBuilder text = new StringBuilder();

    try {
        while (( line = buffreader.readLine()) != null) {
            text.append(line);
            text.append('\n');
        }
    } catch (IOException e) {
        return null;
    }
    return text.toString();
}

10 回复 | 直到 11 年前

nbro kai 6 年前

如果使用基于字符的BufferedReader而不是基于字节的InputStream怎么办?

BufferedReader reader = new BufferedReader(new InputStreamReader(inputStream));
String line = reader.readLine();
while (line != null) { ... }

别忘了 readLine() 跳过新行!

159

Vovodroid 13 年前

您可以使用:

    try {
        Resources res = getResources();
        InputStream in_s = res.openRawResource(R.raw.help);

        byte[] b = new byte[in_s.available()];
        in_s.read(b);
        txtHelp.setText(new String(b));
    } catch (Exception e) {
        // e.printStackTrace();
        txtHelp.setText("Error: can't show help.");
    }

tbraun 9 年前

如果使用apache“commons io”中的IOUtils,则更容易:

InputStream is = getResources().openRawResource(R.raw.yourNewTextFile);
String s = IOUtils.toString(is);
IOUtils.closeQuietly(is); // don't forget to close your streams

依赖项: http://mvnrepository.com/artifact/commons-io/commons-io

马文:

<dependency>
    <groupId>commons-io</groupId>
    <artifactId>commons-io</artifactId>
    <version>2.4</version>
</dependency>

等级:

'commons-io:commons-io:2.4'

Arsenius 5 年前

有了Kotlin,你只需要一行代码就能做到:

resources.openRawResource(R.raw.rawtextsample).bufferedReader().use { it.readText() }

甚至声明扩展函数:

fun Resources.getRawTextFile(@RawRes id: Int) =
        openRawResource(id).bufferedReader().use { it.readText() }

val txtFile = resources.getRawTextFile(R.raw.rawtextsample)

Shankar Narayana Damodaran 11 年前

不如这样做:

// reads resources regardless of their size
public byte[] getResource(int id, Context context) throws IOException {
    Resources resources = context.getResources();
    InputStream is = resources.openRawResource(id);

    ByteArrayOutputStream bout = new ByteArrayOutputStream();

    byte[] readBuffer = new byte[4 * 1024];

    try {
        int read;
        do {
            read = is.read(readBuffer, 0, readBuffer.length);
            if(read == -1) {
                break;
            }
            bout.write(readBuffer, 0, read);
        } while(true);

        return bout.toByteArray();
    }Â finally {
        is.close();
    }
}

    // reads a string resource
public String getStringResource(int id, Charset encoding) throws IOException {
    return new String(getResource(id, getContext()), encoding);
}

    // reads an UTF-8 string resource
public String getStringResource(int id) throws IOException {
    return new String(getResource(id, getContext()), Charset.forName("UTF-8"));
}

从一个 ,添加

public byte[] getResource(int id) throws IOException {
        return getResource(id, this);
}

测试用例 ,添加

public byte[] getResource(int id) throws IOException {
        return getResource(id, getContext());
}

注意你的错误处理-当你的资源必须存在或某事是(非常?)时,不要捕捉和忽略异常。错了。

borislemke 13 年前

这是另一种方法,肯定能用,但我不能让它在一个活动中读取多个文本文件,在多个文本视图中查看,有人能帮忙吗?

TextView helloTxt = (TextView)findViewById(R.id.yourTextView);
    helloTxt.setText(readTxt());
}

private String readTxt(){

 InputStream inputStream = getResources().openRawResource(R.raw.yourTextFile);
 ByteArrayOutputStream byteArrayOutputStream = new ByteArrayOutputStream();

 int i;
try {
i = inputStream.read();
while (i != -1)
  {
   byteArrayOutputStream.write(i);
   i = inputStream.read();
  }
  inputStream.close();
} catch (IOException e) {
 // TODO Auto-generated catch block
e.printStackTrace();
}

 return byteArrayOutputStream.toString();
}

Manish Sharma 12 年前

@borislemke你也可以这样做

TextView  tv ;
findViewById(R.id.idOfTextView);
tv.setText(readNewTxt());
private String readNewTxt(){
InputStream inputStream = getResources().openRawResource(R.raw.yourNewTextFile);
 ByteArrayOutputStream byteArrayOutputStream = new ByteArrayOutputStream();

 int i;
 try {
 i = inputStream.read();
while (i != -1)
  {
   byteArrayOutputStream.write(i);
   i = inputStream.read();
   }
    inputStream.close();
  } catch (IOException e) {
   // TODO Auto-generated catch block
 e.printStackTrace();
 }

 return byteArrayOutputStream.toString();
 }

alcsan 8 年前

它比伏特加溶液更准确,比韦肯溶液更完整。

    try {
        InputStream inputStream = res.openRawResource(resId);
        try {
            BufferedReader reader = new BufferedReader(new InputStreamReader(inputStream));
            try {
                StringBuilder result = new StringBuilder();
                String line;
                while ((line = reader.readLine()) != null) {
                    result.append(line);
                }
                return result.toString();
            } finally {
                reader.close();
            }
        } finally {
            inputStream.close();
        }
    } catch (IOException e) {
        // process exception
    }

Massimiliano Kraus The Angry Programmer 8 年前

1.首先创建一个目录文件夹并将其命名为res文件夹中的raw 3.在创建的.txt文件“articles.txt”中复制并粘贴所需的文本 4.不要忘记在main.xml中包含一个textview main活动.java

@Override
protected void onCreate(Bundle savedInstanceState) {

    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_gettingtoknowthe_os);

    TextView helloTxt = (TextView)findViewById(R.id.gettingtoknowos);
    helloTxt.setText(readTxt());

    ActionBar actionBar = getSupportActionBar();
    actionBar.hide();//to exclude the ActionBar
}

private String readTxt() {

    //getting the .txt file
    InputStream inputStream = getResources().openRawResource(R.raw.articles);

    ByteArrayOutputStream byteArrayOutputStream = new ByteArrayOutputStream();

    try {
        int i = inputStream.read();
        while (i != -1) {
            byteArrayOutputStream.write(i);
            i = inputStream.read();
        }
        inputStream.close();

    } catch (IOException e) {
        e.printStackTrace();
    }
    return byteArrayOutputStream.toString();
}

sakshi agrawal 7 年前

InputStream is=getResources().openRawResource(R.raw.name);
BufferedReader reader=new BufferedReader(new InputStreamReader(is));
StringBuffer data=new StringBuffer();
String line=reader.readLine();
while(line!=null)
{
data.append(line+"\n");
}
tvDetails.seTtext(data.toString());

ucMedia 6 年前

这里有一个简单的方法来读取从 未经加工的 文件夹:

public static String readTextFile(Context context,@RawRes int id){
    InputStream inputStream = context.getResources().openRawResource(id);
    ByteArrayOutputStream outputStream = new ByteArrayOutputStream();

    byte buffer[] = new byte[1024];
    int size;
    try {
        while ((size = inputStream.read(buffer)) != -1) {
            outputStream.write(buffer, 0, size);
        }
        outputStream.close();
        inputStream.close();
    } catch (IOException e) {

    }
    return outputStream.toString();
}

semloh eh 5 年前

这里是Kotlin中的一个实现

    try {
        val inputStream: InputStream = this.getResources().openRawResource(R.raw.**)
        val inputStreamReader = InputStreamReader(inputStream)
        val sb = StringBuilder()
        var line: String?
        val br = BufferedReader(inputStreamReader)
        line = br.readLine()
        while (line != null) {
            sb.append(line)
            line = br.readLine()
        }
        br.close()

        var content : String = sb.toString()
        Log.d(TAG, content)
    } catch (e:Exception){
        Log.d(TAG, e.toString())
    }