XmlDictionaryReader真的能处理二进制XML吗?如果没有,怎么办?

我想写一篇 debugging tool 它允许用户以纯文本形式查看WCF的新二进制XML格式(application/soap+msbin1)。一旦我发现 XmlDictionaryReader 我以为我几分钟后就可以完成,但它没有按预期工作。

private string DecodeBinaryXML(byte[] binaryBuffer)
{
    if (binaryBuffer == null)
    {
        return "";
    }

    try
    {
        var doc = new XmlDocument();
        using (var binaryReader = XmlDictionaryReader.CreateBinaryReader(binaryBuffer, XmlDictionaryReaderQuotas.Max))
        {                    
            doc.Load(binaryReader);
            binaryReader.Close();
        }

        var textBuffer = new StringBuilder();
        var settings = new XmlWriterSettings()
        {
            // lots of code not relevant to the question
        };
        using (var writer = XmlWriter.Create(textBuffer, settings))
        {
            doc.Save(writer);
            writer.Close();
        }

        return textBuffer.ToString();
    }
    catch (Exception ex)
    {
        // just display errors in the text viewer
        return ex.ToString();
    }
}

我在网上找到或自己生成的每个“soap+msbin1”示例都会在处引发分析异常 加载() .

为了了解发生了什么,我创建了一个简单的测试应用程序,并从另一个方向攻击了这个问题。

// client
static void Main(string[] args)
{
    var binding = new CustomBinding(new TextMessageEncodingBindingElement(), 
                                    new HttpTransportBindingElement());            
    var proxy = ChannelFactory<IService1>.CreateChannel(binding, 
               new EndpointAddress("http://ipv4.fiddler:25381/Service1.svc"));
    Console.WriteLine(proxy.Echo("asdf"));
}

// shared interface
[ServiceContract()]
public interface IService1
{
    [OperationContract]
    string Echo(string input);
}

// server
public class Service1 : IService1
{
    public string Echo(string input)
    {
        return "WCF says hi to: " + input;
    }
}

运行它会启动一个HTTP请求,其外观如下:

<s:Envelope xmlns:s="http://www.w3.org/2003/05/soap-envelope" 
            xmlns:a="http://www.w3.org/2005/08/addressing">
  <s:Header>
     <a:Action s:mustUnderstand="1">http://tempuri.org/IService1/Echo</a:Action>
     <a:MessageID>urn:uuid:21a33e81-bfab-424f-a2e5-5116101a7319</a:MessageID>
     <a:ReplyTo>
        <a:Address>http://www.w3.org/2005/08/addressing/anonymous</a:Address>
     </a:ReplyTo>
     <a:To s:mustUnderstand="1">http://ipv4.fiddler:25381/Service1.svc</a:To>
  </s:Header>

  <s:Body>
      <Echo xmlns="http://tempuri.org/">
          <input>asdf</input>
      </Echo>
  </s:Body>
</s:Envelope>

我转换了这个XML 进入之内 两种不同的二进制方式。首先,使用xmlDictionaryWriter:

$fs = [system.io.file]::Create("c:\temp\soap.bin")
$writer = [system.xml.xmldictionarywriter]::CreateBinaryWriter($fs)
$xml = [xml] (gc C:\temp\soap.xml)
$xml.Save($writer)
$writer.Close(); $fs.Close()

然后,使用WCF和相同的网络嗅探器:

    @@ -1,7 +1,7 @@
     // client
     static void Main(string[] args)
     {
-        var binding = new CustomBinding(new TextMessageEncodingBindingElement(), 
+        var binding = new CustomBinding(new BinaryMessageEncodingBindingElement(), 
                                         new HttpTransportBindingElement()); 

方法1给出了397个字节的二进制格式。方法2显示169个字节的非常不同的二进制文件。除了在两个输出中出现的一些字符串之外,在两个编码中我看不到太多的相似性。难怪xmlDictionaryReader无法理解WCF服务的输出!

解码这种格式有什么秘密吗,还是我完全走错了路?