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确保静态键存在于另一个类上

typescript

ThomasReggi · 技术社区 · 5 年前

我正在寻找一种方法来确保一个类中的所有属性都存在于另一个类中。

export class Components {
    static [Pages.home] = Home.Page
    static [Pages.login] = Login.Page
    static [Pages.logout] = Logout.Page
    static [Pages.dashboardManage] = DashboardManage.Page
    static [Pages.dashboardOrganizationTable] = DashboardOrganizationTable.Page
    static [Pages.organizationSettings] = OrganizationSettings.Page
}

export class Resolvers implements Components {
    static [Pages.home] = Home.Page
    static [Pages.login] = Login.Page
    static [Pages.logout] = Logout.Page
    static [Pages.dashboardManage] = DashboardManage.Page
    static [Pages.dashboardOrganizationTable] = DashboardOrganizationTable.Page
    static [Pages.organizationSettings] = OrganizationSettings.Page
}

implements Components 不起作用

我也试过:

type PagesInUse = keyof typeof Components
type ExmapB = {[key in PagesInUse]: any}

1 回复 | 直到 5 年前

ThomasReggi 5 年前

这适用于常规对象:

export const Components = {
    [Pages.home]: Home.Page,
    [Pages.login]: Login.Page,
    [Pages.logout]: Logout.Page,
    [Pages.dashboardManage]: DashboardManage.Page,
    [Pages.dashboardOrganizationTable]: DashboardOrganizationTable.Page,
    [Pages.organizationSettings]: OrganizationSettings.Page,
}

type PageKeysInUse = keyof typeof Components
type PagesInUse = { [key in PageKeysInUse]: any }

export const Resolvers: PagesInUse = {
    [Pages.home]: Home.Page,
    [Pages.login]: Login.Page,
    [Pages.logout]: Logout.Page,
    [Pages.dashboardManage]: DashboardManage.Page,
    [Pages.dashboardOrganizationTable]: DashboardOrganizationTable.Page,
    [Pages.organizationSettings]: OrganizationSettings.Page,
}

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