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基于公共值将对象合并到多维数组

merge multidimensional-array object arrays javascript

sonja · 技术社区 · 6 年前

我正在寻找一种基于公共值将对象合并到数组中的方法。我的解决方案应该是动态的,这会给我带来很多麻烦。下面是一个例子:

我有一个多维数组(见下面的代码)。它包含一个名为“w·hrung”的列,该列具有数值。

0: {AGIMENDO Info Objekt 1: "00000000", Beschreibung Kurz: "Test0", WÃ¤hrung: "200.00", __rowNum__: 1}
1: {AGIMENDO Info Objekt 1: "00000001", Beschreibung Kurz: "Update1", WÃ¤hrung: "456.00", __rowNum__: 2}
2: {AGIMENDO Info Objekt 1: "00000002", Beschreibung Kurz: "Test2", WÃ¤hrung: "12.00", __rowNum__: 3}
3: {AGIMENDO Info Objekt 1: "00000003", Beschreibung Kurz: "Test3", WÃ¤hrung: "549153.00", __rowNum__: 4}
4: {AGIMENDO Info Objekt 1: "00000004", Beschreibung Kurz: "Text", WÃ¤hrung: "1.05", __rowNum__: 5}
5: {AGIMENDO Info Objekt 1: "00000005", Beschreibung Kurz: "13.08.11", WÃ¤hrung: "465.00", __rowNum__: 6}
6: {AGIMENDO Info Objekt 1: "00000006", Beschreibung Kurz: "Test21", WÃ¤hrung: "4594.00", __rowNum__: 7}

对于每一行,我遍历每个单元格,并为每个包含数值/日期值的单元格分配一个“类型”。下面的代码显示了这个数组。现在我想基于公共值合并这两个数组(第一个数组是“w··hrung”,第二个数组是“value”)。我试过使用lodash uu.map,u.assign等,但没有得到我想要的输出。

0: {type: "number", value: "200.00"}
1: {type: "number", value: "456.00"}
2: {type: "number", value: "12.00"}
3: {type: "number", value: "549153.00"}
4: {type: "number", value: "1.05"}
5: {type: "date", value: "13.08.11"}
6: {type: "number", value: "465.00"}

我的目标输出如下(第一行):

> 0:
>   AGIMENDO Info Objekt1: "00000000"
>   Beschreibung Kurz: "Test0" 
>   WÃ¤hrung:
>     Value : "200.00" 
>     Type: "number"

我怎样才能做到这一点?

3 回复 | 直到 6 年前

barbsan Cibi 6 年前

如果第二个数组包含具有相同值的对象,则必须循环遍历所有属性并替换值。

var arr1, arr2, result;

arr1 = [
  {"AGIMENDO Info Objekt 1": "00000000", "Beschreibung Kurz": "Test0", WÃ¤hrung: "200.00", __rowNum__: 1},
  {"AGIMENDO Info Objekt 1": "00000001", "Beschreibung Kurz": "Update1", WÃ¤hrung: "456.00", __rowNum__: 2},
  {"AGIMENDO Info Objekt 1": "00000002", "Beschreibung Kurz": "Test2", WÃ¤hrung: "12.00", __rowNum__: 3},
  {"AGIMENDO Info Objekt 1": "00000003", "Beschreibung Kurz": "Test3", WÃ¤hrung: "549153.00", __rowNum__: 4},
  {"AGIMENDO Info Objekt 1": "00000004", "Beschreibung Kurz": "Text", WÃ¤hrung: "1.05", __rowNum__: 5},
  {"AGIMENDO Info Objekt 1": "00000005", "Beschreibung Kurz": "13.08.11", WÃ¤hrung: "465.00", __rowNum__: 6},
  {"AGIMENDO Info Objekt 1": "00000006", "Beschreibung Kurz": "Test21", WÃ¤hrung: "4594.00", __rowNum__: 7}
];

arr2 = [
  {type: "number", value: "200.00"},
  {type: "number", value: "456.00"},
  {type: "number", value: "12.00"},
  {type: "number", value: "549153.00"},
  {type: "number", value: "1.05"},
  {type: "date", value: "13.08.11"},
  {type: "number", value: "465.00"}
       ]

result = arr1.map(obj=>{
  let copy = Object.assign({}, obj);
  Object.entries(obj).forEach(([key, val])=>{
    let type = arr2.find(el=>el.value === val);
    if (type){
      copy[key] = type;
    }
  })
  return copy;
})

console.log(result)

evgeni fotia 6 年前

我不确定你是否愿意 __rowNum__ 是否在外面

var arrA = [{'AGIMENDO Info Objekt 1': "00000000", 'Beschreibung Kurz': "Test0", 'WÃ¤hrung': "200.00", '__rowNum__': 1}, {'AGIMENDO Info Objekt 1': "00000001", 'Beschreibung Kurz': "Update1", 'WÃ¤hrung': "456.00", '__rowNum__': 2}];

var arrB = [{type: "number", value: "200.00"}, {type: "number", value: "456.00"}];

var resultat = arrA.map((obj, index)=>(    Object.assign(obj, {'WÃ¤hrung': {
     'Value': arrB[index].value,
     'Type': arrB[index].type
  }})
));

console.log(resultat);

Vishnudev Krishnadas 6 年前

这应该可以工作,因为您可以直接更新json数组

json_arr = [{"AGIMENDO Info Objekt 1": "00000000", "Beschreibung Kurz": "Test0", "WÃ¤hrung": "200.00", "__rowNum__": 1},
 {"AGIMENDO Info Objekt 1": "00000001", "Beschreibung Kurz": "Update1", "WÃ¤hrung": "456.00", "__rowNum__": 2}]

function update_type(json_arr, column_name) {    
    for(var i=0; i<json_arr.length; i++){
        element = json_arr[i][column_name];
        json_arr[i][column_name] = {};
        json_arr[i][column_name]['value'] = element;
        json_arr[i][column_name]['type'] = get_type(json_arr[i][column_name]); /* Here comes your type checking function */
   }
   return json_arr
}
console.log(update_type(json_arr, "WÃ¤hrung"))