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SQL搜索和销毁重复项

oracle9i duplicates oracle sql

Carl Smotricz · 技术社区 · 15 年前

我有一个带有字段的表(简化):

id, fld1, fld2, fld3.

id 是数字主键字段。

有重复项: 身份证件 不同但 fld1 , fld2 和 fld3 两行或多行相同。当然,也有一些条目的值只出现一次,即不重复。

在每一组重复的条目中,我只想保留ID最高的条目。我计划先列出注定要失败的行,然后删除它们。

我第一次尝试的是:

SELECT * FROM tab1 t1 WHERE EXISTS (
  SELECT COUNT(*) FROM tab1 t2
  WHERE t1.fld1 = t2.fld1 AND t1.fld2 = t2.fld2 AND t1.fld3 = t2.fld3
    AND t1.id < MAX(t2.id)
  HAVING COUNT(*) > 1
  GROUP BY t2.fld1, t2.fld2, t2.fld3)

但是(在甲骨文中)我得到了 Missing right parenthesis 错误消息。我认为这完全需要一种新的方法,但我的SQL fu不能胜任这项任务。感谢您的帮助!

编辑:

使用“真实”数据字段:

select x.leg_id, x.airline_des, x.flight_nr, x.suffix, x.flight_id_date, x.lt_flight_id_date
from fdb_leg x
join ( select max(t.leg_id) 'max_id', 
t.airline_des, t.flight_nr, t.suffix, t.flight_id_date, t.lt_flight_id_date
from fdb_leg t
group by t.airline_des, t.flight_nr, t.suffix, t.flight_id_date, t.lt_flight_id_date
having count(*) > 1) y on y.max_id > x.leg_id
and y.airline_des = x.airline_des and y.flight_nr = x.flight_nr and y.suffix = x.suffix
and y.flight_id_date = x.flight_id_date and x.lt_flight_id_date = y.lt_flight_id_date

反应是:

ORA-00923:在预期的位置找不到FROM关键字

3 回复 | 直到 15 年前

OMG Ponies 15 年前

Oracle 9i+,用于:

要获取注定失败的条目列表,请使用:

WITH keepers AS (
   SELECT MAX(t.id) 'max_id',
          t.fld1, t.fld2, t.fld3
     FROM TABLE_1 t
 GROUP BY t.fld1, t.fld2, t.fld3
   HAVING COUNT(*) > 1)
SELECT x.id,
       x.fld1, x.fld2, x.fld3
  FROM TABLE_1 x
  JOIN keepers y ON y.max_id > x.id
                AND y.fld1 = x.fld1
                AND y.fld2 = x.fld2
                AND y.fld3 = x.fld3

不含等价物:

要获取注定失败的条目列表,请使用:

SELECT x.id,
       x.fld1, x.fld2, x.fld3
  FROM TABLE_1 x
  JOIN (SELECT MAX(t.id) 'max_id',
               t.fld1, t.fld2, t.fld3
          FROM TABLE_1 t
      GROUP BY t.fld1, t.fld2, t.fld3
        HAVING COUNT(*) > 1) y ON y.max_id > x.id
                              AND y.fld1 = x.fld1
                              AND y.fld2 = x.fld2
                              AND y.fld3 = x.fld3

Rob van Wijk 15 年前

您可以一次删除它们,如下所示:

SQL> create table mytable (id, fld1, fld2, fld3)
  2  as
  3  select 1, 1, 1, 1 from dual union all
  4  select 2, 1, 1, 1 from dual union all
  5  select 3, 2, 2, 2 from dual union all
  6  select 4, 2, 3, 2 from dual union all
  7  select 5, 2, 3, 2 from dual union all
  8  select 6, 2, 3, 2 from dual
  9  /

Table created.

SQL> delete mytable
  2   where id not in
  3         ( select max(id)
  4             from mytable
  5            group by fld1
  6                , fld2
  7                , fld3
  8         )
  9  /

3 rows deleted.

SQL> select * from mytable
  2  /

        ID       FLD1       FLD2       FLD3
---------- ---------- ---------- ----------
         2          1          1          1
         3          2          2          2
         6          2          3          2

3 rows selected.

当做, 罗布。

-1

JeffO 15 年前

呃,我明白了。搔那个。

这将标识需要删除的ID。

Select 
       fld1
     , fld2
     , fld3
     , Max(ID)
From table_name
Group By
       fld1
     , fld2
     , fld3