将箭头函数移动到另一个导出函数

我有问题。我想清除我的代码并将函数放到另一个文件中,但我总是得到一个错误:

getMe is not a function

为什么?我想在已经导出的函数getExchangeRateIntent中使用它。这会引起问题吗?

JS

const getRate = (base) => {
  console.log('My base currency is '+base);
};

module.exports = {getRate};

GeTrATE.JS

const getMe = ('./outside.js');

module.exports = {

  'getExchangeRateIntent': (conv, parameter) => {
    const currencyBase = (parameter['currencyBase']);
    const currencyTarget = (parameter['currencyTarget']);
    const amount = (parameter['amount']);
    console.log(currencyBase);
    console.log(currencyTarget);
    console.log(amount);

    getMe('USD');

    conv.ask('nothing');
  },

};