访问多行多对多关系的SQL选择值

使用查询生成器设计视图帮助生成SQL语句。结果应该是:

SELECT ricette.nome, ingredienti.nome
FROM ingredienti 
RIGHT JOIN (ricette RIGHT JOIN ricetta_ingrediente 
            ON ricette.ID = ricetta_ingrediente.id_ricetta) 
ON ingredienti.ID = ricetta_ingrediente.id_ingrediente;

要检索包含最多成分和成分的配方,例如:

SELECT TOP 1 ricette.nome, ingredienti.nome
FROM (SELECT id_ricetta, Count([id_ingrediente]) AS CountIng
      FROM ricetta_ingrediente GROUP BY id_ricetta) AS Q1
RIGHT JOIN (ricette RIGHT JOIN (ingredienti RIGHT JOIN ricetta_ingrediente 
                                ON ingredienti.ID = ricetta_ingrediente.id_ingrediente) 
            ON ricette.ID = ricetta_ingrediente.id_ricetta) 
ON Q1.id_ricetta = ricetta_ingrediente.id_ricetta
ORDER BY Q1.CountIng DESC;

这不会解决关系。所有成分数量与前1个计数匹配的配方都将返回。查询应该如何知道您只需要1和哪一个?

你的问题还可以。您只需要括号,因为这是MS Access。

我还将使用表别名:

SELECT r.nome, i.nome
FROM (ricette as r INNER JOIN
      ricetta_ingrediente as ri
      ON r.ID = ri.id_ricetta
     ) INNER JOIN
     ingredienti as i
     ON i.ID = ri.id_ingrediente;

编辑:

对于修订后的问题:

SELECT TOP (1) r.nome
FROM (ricette as r INNER JOIN
      ricetta_ingrediente as ri
      ON r.ID = ri.id_ricetta
     ) INNER JOIN
     ingredienti as i
     ON i.ID = ri.id_ingrediente
GROUP BY r.nome
ORDER BY COUNT(*) DESC;