Python-For循环-仅当上述行相等时才打印

要从仅与列表中最后一个字符匹配的列表中提取字符,可以执行以下操作:

characters = ['a', 'b', 'b', 'c','d', 'b']

for i in range(0, len(characters) - 1):
    if characters[i] == characters[-1]:
        print(characters[i])

i

a = ['a', 'b', 'b', 'c', 'd', 'b']
b = ['a', 'b', 'b', 'c', 'd', 'b', 'd']

import collections

print([item for item, count in collections.Counter(a).items() if count > 1])
print([item for item, count in collections.Counter(b).items() if count > 1])

输出

['b']
['b', 'd']

而不是在同一个列表上重复多次。

characters = ['a', 'b', 'b', 'c','d', 'b']
last_char = None

output = []

for char in characters:
    if char == last_char:
        output.append(char)
    last_char = char

print(output)

equal = [a for a in characters[0:-1] if a == characters[-1]]

equal = [a for a in characters if a == characters[-1]]

代码中的小修改

characters = ['a', 'b', 'b', 'c','d', 'b']
ch=  (characters[-1])
for i in characters:
    if i == ch:
        print(i