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PHP Slim 3-在Slim路由中访问类对象实例

slim-3 instance routes object php

SneakyShrike · 技术社区 · 6 年前

所以我正在学习如何编写一个slim3php身份验证应用程序,我正在使用一个示例代码结构开始。示例代码中有一个名为dependencies.php的文件,该文件包含一系列创建其他类的对象实例的函数。然后将它们分配给一个$container变量,并为每个函数指定一个名称。dependencies.php文件中的函数示例如下:

$container['view'] = function ($container) {
    $view = new \Slim\Views\Twig(
        $container['settings']['view']['template_path'],
        $container['settings']['view']['twig'],
        [
            'debug' => true // This line should enable debug mode
        ]
    );

    $basePath = rtrim(str_ireplace('index.php', '', $container['request']->getUri()->getBasePath()), '/');
    $view->addExtension(new Slim\Views\TwigExtension($container['router'], $basePath));

    $view->addExtension(new \Twig_Extension_Debug());

    return $view;
};

$container['validate_sanitize'] = function ($container)
{
    $class_path = $container->get('settings')['class_path'];
    require $class_path . 'ValidateSanitize.php';
    $validator = new ValidateSanitize();
    return $validator;
};

$container['hash_password'] = function($container)
{
    $class_path = $container->get('settings')['class_path'];
    require $class_path . 'HashPassword.php';
    $hash = new HashPassword();
    return $hash;
};

然后在我的slim routes中以某种方式调用这些函数。例如在我的 register.php validate_sanitize

$this->get(âvalidate_sanitizeâ);

并赋给一个变量,然后我可以使用该变量从 验证\u消毒 班级。

然而我不明白的是这是怎么回事 get 方法用于从dependencies.php文件调用类对象。

$app->post('/register', function(Request $request, Response $response)
{
    $arr_tainted_params = $request->getParsedBody();

    $sanitizer_validator = $this->get('validate_sanitize'); //here for example
    $password_hasher = $this->get('hash_password');

    $tainted_email = $arr_tainted_params['email'];
    $tainted_username = $arr_tainted_params['username'];
    $tainted_password = $arr_tainted_params['password'];

    $model = $this->get('model');
    $sql_wrapper = $this->get('sql_wrapper');
    $sql_queries = $this->get('sql_queries');
    $db_handle = $this->get('dbase');

    $cleaned_email = $sanitizer_validator->sanitize_input($tainted_email, FILTER_SANITIZE_EMAIL);
    $cleaned_username = $sanitizer_validator->sanitize_input($tainted_username, FILTER_SANITIZE_STRING);
    $cleaned_password = $sanitizer_validator->sanitize_input($tainted_password, FILTER_SANITIZE_STRING);
 });

我的所有路由都包含在routes.php文件中,该文件如下所示:

 <?php

require 'routes/change_password.php';
require 'routes/forgot_password.php';
require 'routes/homepage.php';
require 'routes/login.php';
require 'routes/logout.php';
require 'routes/register.php';

还有一个引导文件,它创建了一个新的Slim容器Slim App instance,还包括必要的文件。我也不完全确定什么是超薄容器或者它是做什么的。此引导文件如下所示:

<?php

session_start();

require __DIR__ . '/../vendor/autoload.php';

$settings = require __DIR__ . '/app/settings.php'; //an array of options containing database configurations and the path to twig templates

$container = new \Slim\Container($settings); //not sure what this does

require __DIR__ . '/app/dependencies.php';

$app = new \Slim\App($container);

require __DIR__ . '/app/routes.php';

$appârun();

谢谢。

1 回复 | 直到 6 年前

Zamrony P. Juhara 4 年前

内部路由可调用, $this $container 实例。

map() 方法 Slim\App 类,您将看到以下代码:

if ($callable instanceof Closure) {
   $callable = $callable->bindTo($this->container);
}

bindTo() 是什么使您可以使用 $这个 变量。

<?php 
namespace App\Controller;

class MyPostRegisterController
{
    private $container;

    public function __constructor($container)
    {
        $this->container = $container;
    }

    public function __invoke(Request $request, Response $response)
    {
        $sanitizer_validator = $this->container->get('validate_sanitize'); 
        //do something
    }
}

然后您可以如下定义路由

$app->post('/register', App\Controller\MyPostRegisterController::class);

MyPostController 类,它尝试创建它们并传递容器实例。

若要调用其他方法,请在用冒号分隔的类名之后附加方法名。例如,以下 route registration 将调用方法 home()

$app->post('/register', App\Controller\MyPostRegisterController::class . ':home');