Python实现

这不在PHP中,但如果你想解码谷歌地图中的折线字符串,这个线程就在搜索结果的顶部附近。如果其他人需要它(和我一样),这里有一个用于解码多段线字符串的Python实现。这是从Mapbox JavaScript版本移植过来的;在我的上找到更多信息 repo page.

def decode_polyline(polyline_str):
    index, lat, lng = 0, 0, 0
    coordinates = []
    changes = {'latitude': 0, 'longitude': 0}

    # Coordinates have variable length when encoded, so just keep
    # track of whether we've hit the end of the string. In each
    # while loop iteration, a single coordinate is decoded.
    while index < len(polyline_str):
        # Gather lat/lon changes, store them in a dictionary to apply them later
        for unit in ['latitude', 'longitude']: 
            shift, result = 0, 0

            while True:
                byte = ord(polyline_str[index]) - 63
                index+=1
                result |= (byte & 0x1f) << shift
                shift += 5
                if not byte >= 0x20:
                    break

            if (result & 1):
                changes[unit] = ~(result >> 1)
            else:
                changes[unit] = (result >> 1)

        lat += changes['latitude']
        lng += changes['longitude']

        coordinates.append((lat / 100000.0, lng / 100000.0))

    return coordinates

您可以在Github上查看此回购: Google Maps Polyline Encoding Tool

一个简单的PHP类,用于将折线转换为谷歌地图的编码字符串。

<?php

# Do steps 1-11 given here 
# https://developers.google.com/maps/documentation/utilities/polylinealgorithm
# in reverse order and inverted (i.e. left shift -> right shift, add -> subtract)

$string = "udgiEctkwIldeRe}|x@cfmXq|flA`nrvApihC";
# Step 11) unpack the string as unsigned char 'C'
$byte_array = array_merge(unpack('C*', $string));
$results = array();

$index = 0; # tracks which char in $byte_array
do {
  $shift = 0;
  $result = 0;
  do {
    $char = $byte_array[$index] - 63; # Step 10
    # Steps 9-5
    # get the least significat 5 bits from the byte
    # and bitwise-or it into the result
    $result |= ($char & 0x1F) << (5 * $shift);
    $shift++; $index++;
  } while ($char >= 0x20); # Step 8 most significant bit in each six bit chunk
    # is set to 1 if there is a chunk after it and zero if it's the last one
    # so if char is less than 0x20 (0b100000), then it is the last chunk in that num

  # Step 3-5) sign will be stored in least significant bit, if it's one, then 
  # the original value was negated per step 5, so negate again
  if ($result & 1)
    $result = ~$result;
  # Step 4-1) shift off the sign bit by right-shifting and multiply by 1E-5
  $result = ($result >> 1) * 0.00001;
  $results[] = $result;
} while ($index < count($byte_array));

# to save space, lat/lons are deltas from the one that preceded them, so we need to 
# adjust all the lat/lon pairs after the first pair
for ($i = 2; $i < count($results); $i++) {
  $results[$i] += $results[$i - 2];
}

# chunk the array into pairs of lat/lon values
var_dump(array_chunk($results, 2));

# Test correctness by using Google's polylineutility here:
# https://developers.google.com/maps/documentation/utilities/polylineutility

?>

这个问题最简单的解决办法。。

这是一个 Link 到Github Repo,其中包括用于编码/解码的类。它也有尽可能简单的用法描述。

注意: 为了解码while循环中的最后一行,函数decodeValue中的多段线,我不得不稍微更改类。我曾经 将100000替换为1000000

$points[] = array('x' => $lat/1000000, 'y' => $lng/1000000);