Found it here.
您只需要检索文件和文件夹ID,然后使用更新方法。如果要将文件副本保留在旧文件夹中,可以排除remove_parents参数
file_id = '***'
folder_id = '***'
# Retrieve the existing parents to remove
file = drive_service.files().get(fileId=file_id, fields='parents').execute()
previous_parents = ",".join(file.get('parents'))
# Move the file to the new folder
file = drive_service.files().update(
fileId=file_id,
addParents=folder_id,
removeParents=previous_parents,
fields='id, parents'
).execute()
(注意,我没有包括我的基本助手函数_getFileId和_getFolderId),所以我的原始函数看起来像:
def move_file(service, filename, init_drive_path, drive_path, copy=False):
"""Moves a file in Google Drive from one location to another.
service: Drive API service instance.
'filename' (string): file path on local machine, or a bytestream
to use as a file.
'init_drive_path' (string): the file path the file was initially in on Google
Drive (in <folder>/<folder>/<folder> format).
'drive_path' (string): the file path to move the file in on Google
Drive (in <folder>/<folder>/<folder> format).
'copy' (boolean): file should be saved in both locations
Returns nothing.
"""
file_id = _getFileId(service, filename, init_drive_path)
folder_id = _getFolderId(service, drive_path)
if not file_id or not folder_id:
raise Exception('Did not find file specefied: {}/{}'.format(init_drive_path, filename))
file = service.files().get(fileId=file_id, fields='parents').execute()
if copy:
previous_parents = ''
else:
previous_parents = ",".join(file.get('parents'))
file = drive_service.files().update(
fileId=file_id,
addParents=folder_id,
removeParents=previous_parents,
fields='id, parents'
).execute()