带复合键的单亲家庭

用户有2个组合键

class TireId {
 private String uId;
 private String schoolId
}

用户实体:

@IdClass(UserId.class)
@Entity
Class User {

 @Id
 private String uId;
 @Id
 private String schoolId

    @OneToMany(mappedBy="user")
    private List<Bottom> bottoms;


}

下装:

class BottomId {
   private String bId;
   private String cId;
   private String schoolId;

}

底层:

@IdClass(BottomId.class) 
@Entity
class Bottom {
    private String bId;
   private String cId;
   private String schoolId;
    @ManyToOne
   private  User user;
}

在上述情况下,hibernate将在下表名user-uId和user-schoolId中创建另外两列。

但我需要一个有以下关系的用户

schoolId of user == schoolId of Bottom
and uId of user == cId of of Bottom