python三元if语句不捕捉None

例如

first: 7 -> 1 -> 6      617
second: 5 -> 9 -> 2    +295
                       -----
                        912
output: 2 -> 1 -> 9 ( which indicates 912 )

这是我的密码,

class Node:
    def __init__(self, val=None):
        self.data = val
        self.Next = None

class LinkedList:
    def __init__(self):
        self.head = None
        self.size = 0

    def __repr__(self):
        temp = self.head
        alist = []
        while temp:
            alist.append(temp.data)
            temp = temp.Next
        return str(alist)

    def add(self, val):
        cur = self.head
        prev = None
        if cur is None:
            self.head = Node(val)
        else:
            while cur:
                prev = cur
                cur = cur.Next
            prev.Next = Node(val)
        self.size += 1

def adding(p1,p2):
    pointer1 = p1.head
    pointer2 = p2.head
    remainder = 0
    sum_list = LinkedList()

    while pointer1 is not None or pointer2 is not None:
        first = 0 if pointer1.data is None else pointer1.data
        second = 0 if pointer2.data is None else pointer2.data
        sum_ = first + second + remainder

        remainder = 1 if sum_ >= 10 else 0

        sum_ %= 10

        sum_list.add(sum_)

        if pointer1 is not None:
            pointer1 = pointer1.Next
        if pointer2 is not None:
            pointer2 = pointer2.Next
    if remainder > 0:
        sum_list.add(remainder)
    return sum_list

我的问题是 first = 0 if pointer1.data is None else pointer1.data 当两个链表的大小相同时,它会起作用,但是,如果其中一个链表比其他链表短,则较短的链表会变短 None .所以我希望if语句捕捉到这一点,并将变量(第一个)作为 0 .但它抛出 AttributeError: NoneType object has no attribute 'data' .

如果我写得正常,它会工作,而不是 ternary operator

if pointer1 is None:
    first = 0
else:
    first = pointer1.data
if pointer2 is None:
    second = 0
else:
    second = pointer2.data

三元运算符 ? 谢谢